All categories

3 years ago

A girl is sitting in a sled sliding horizontally along some snow (there is friction present).

Physics

1 answer:

Mariulka [41]3 years ago

5 0

Answer:

159 N

Explanation:

There are two types of force of friction:

- Static friction: this is the force of friction that occurs when the object is at rest

- Kinetic friction: this is the force of friction that occurs when the object is in motion

In this problem, the girl is sitting on the sled, and the sled is sliding: this means that the object is in motion, therefore the force of friction that we have to calculate in this problem is the force of kinetic friction.

The force of kinetic friction acting on an object sliding over a flat surface is given by

$F_f = \mu_k N$

where

$\mu_k$ is the coefficient of kinetic friction

N is the normal force on the object

In this problem:

$\mu_k = 0.25$

N = 636 N

Therefore, the force of kinetic friction is

$F_f=(0.25)(636)=159 N$

You might be interested in

Someone please help me with this physics!

Taya2010 [7]

When it leaves the hand, it's rising at 18.2 m/s. After 1 second, gravity has slowed it to (18.2 - 9.8) = 8.4 m/s, still rising. Its average speed during the first second is 1/2 of (18.2 + 8.4) = 13.3 m/s. Rising for 1 second at an average speed of 13.3 m/s, it rises 13.3m from the hand.

8 0

3 years ago

2.5 years into minutes?<br><br>

Mnenie [13.5K]

Is it 1314000 Or something

8 0

3 years ago

A cue ball initially moving at 3.4 m/s strikes a stationary eight ball of the same size and mass. After the collision, the cue b

romanna [79]

Answer:

speed of eight ball speed after the collision is 3.27 m/s

Explanation:

given data

initially moving v1i = 3.4 m/s

final speed is v1f = 0.94 m/s

angle = θ w.r.t. original line of motion

solution

we assume elastic collision

so here using conservation of energy

initial kinetic energy = final kinetic energy .............1

before collision kinetic energy = 0.5 × m× (v1i)²

and

after collision kinetic energy = 0.5 × m× (v1f)² + 0.5 × m× (v2f)²

put in equation 1

0.5 × m× (v1i)² = 0.5 × m× (v1f)² + 0.5 × m× (v2f)²

(v2f)² = (v1i)² - (v1f)²

(v2f)² = 3.4² - 0.94²

(v2f)² = 10.68

taking the square root both

v2f = 3.27 m/s

speed of eight ball speed after the collision is 3.27 m/s

5 0

3 years ago

if a body of mass 2kg travels with 2 m/s and other body of mass 2kg travels with 1m/s then find v1 and v2 in given statement

KIM [24]

Answer:

Your answer is here,

Explanation:

v1 = 4 kg m/s

v2 = 2 kg m/s

8 0

3 years ago

Which choice below shows the order of degrees from least specialized to most specialized? Select the best answer choice.

g100num [7]

The answer to this question is A my friend I hope this helps yah

5 0

4 years ago

Read 2 more answers