A 500 N passenger weighs 24500 N elevator that rises 30 m in exactly 1 minute how much power is needed for the elevators trip
1 answer:
Answer:
12500 W (12.5 kW)
Explanation:
The total weight of the passenger + elevator is
The total work done to rise the elevator + passenger is equal to the product between the total weight and the distance covered during the trip (d = 30 m):
The power needed for the trip is equal to the ratio between the work done (W) and the time taken (t):
Since the time taken is t = 1 min = 60 s, the power needed is
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