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Kaylis [27]
3 years ago
15

Hydrogenotrophy is Choose one: A. an award given to fuel companies that have the most fuel-efficient vehicles. B. the oxidation

of water during photosynthesis to liberate electrons, protons, and oxygen gas. C. the use of hydrogen gas as an electron donor. D. the generation of hydrogen gas by methanogens in syntrophy.
Chemistry
1 answer:
Mrrafil [7]3 years ago
8 0

Answer:

C. the use of hydrogen gas as an electron donor.

Explanation:

Hydrogenotrophy is the convertion of hydrogen gas to other compounds as part of its metabolism.

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How many total atoms are in 0.920 g of P2O5?
lions [1.4K]
Molar mass P2O5 = 31 x 2 + 16 x 5 => 142 g/mol


142 g ---------------- 6.02 x 10²³ molecules
0.920g g ------------ ( molecules )

molecules = 0.920 x ( 6.02 x 10²³ ) / 142

molecules = 5.53 x 10²³ / 142

= 3.89 x 10²¹ molecules

1 molecule P2O5 -------------------------- 7 atoms
3.89 x 10²¹ molecules -------------------- ( atoms )

atoms = ( 3.89 x 10²¹) x 7 / 1

atoms = 2.72 x 10²² atoms of P2O5

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3 years ago
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Blank moles of carbon dioxide are required to make 7.2 moles of glucose. A plant using 618 grams of carbon dioxide and plenty of
Virty [35]

Answer:

43.2 moles of carbon dioxide are required and 421g of glucose could be produced

Explanation:

Based on the reaction:

6CO2 + 6H2O → C6H12O6 + 6O2

1 mole of glucose, C6H12O6, requires 6 moles of carbon dioxide. 7.2moles of glucose requires:

7.2mol C6H12O6 * (6mol CO2 / 1mol C6H12O6) =

<h3>43.2 moles of carbon dioxide are required</h3><h3 />

618g of CO2 -Molar mass: 44.01g/mol- are:

618g * (1mol / 44.01g) = 14.04moles CO2

Moles C6H12O6:

14.04moles CO2 * (1mol C6H12O6 / 6mol CO2) = 2.34moles C6H12O6

Mass glucose -Molar mass: 180.156g/mol-

2.34moles C6H12O6 * (180.156g / mol) =

<h3>421g of glucose could be produced</h3>
7 0
3 years ago
Write the pair sequence using the right base for the mouse DNA. ATGGGTGATGTTGAAAAAGGCAAGAAGATTTTTGTTCAGAAGTGTGCCCAGTGCCACACT
inysia [295]

Answer:

Explanation:

Every A will be paired with a T, and every C with a G and vice versa (T to A, and G to C)

So the first letters in the sequence are ATGGG. So the pair will be TACCC.

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3 years ago
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