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Ivan
3 years ago
12

The compressibility factor of any gas at a specific value of reduced temperature, T Tc, and reduced pressure, P Pc does not have

approximately the same value for all species. Select one: True False
Chemistry
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

False

Explanation:

According to principle of corresponding state, at reduced states or corresponding state, behavior of all gases are similar.

This principle is proposed by van der Waals.

In other words, all gases at same reduced temperature, reduced pressure and reduced volume deviate from ideal gas behavior to the same degree or have same compressibility factor.

Reduced quantities are defined as:

Reduced pressure P_R = \frac{P}{P_c}

Reduced temperature T_R = \frac{T}{T_c}

Reduced volume V_R = \frac{V}{V_c}

Where,

P_c = Critical pressure

V_c = Critical volume

T_c = Critical temperature

The compressibility factor (Z_c) at critical temperature is given by,

                                      Z_c=\frac{P_c V_c}{n_c k_B T_c}

Crtitical parameters (critical temperaures, critical pressure and critical volume) can be expressed in terms of van der Waals parameters a and b.

Principle of corresponding state can also be stated as gases at the same reduced pressure and reduced temperature have same reduced volume.

Hence, compressibility factor at reduced state will be same for all gase. so the given statement is false.

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Bond [772]

Answer:

ΔH = -793,6 kJ

Explanation:

It is possible to obtain ΔH of this reaction using Hess's law that says you can sum the half-reactions ΔH to obtain the ΔH of the global reaction:

If half-reactions are:

1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁ = −241.8 kJ

2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂ = +356.9 kJ  

3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl(g) ΔH₃ = −92.3 kJ

4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄ = −639.1 kJ

5) H₂O(g) ⟶ H₂O(l) ΔH₅ = −44.0 kJ

The sum of (4) + 4×(3) - (2) - 2×(1) - 2×(5) is:

(4) X(s) + O₂(g) ⟶ XO₂(s) ΔH = −639.1 kJ

+4×(3) 2H₂(g) + 2Cl₂(g) ⟶ 4HCl(g) ΔH = −369,2 kJ

-(2) XCl₄(s) ⟶ X(s) + 2Cl₂(g) ΔH = -356,9 kJ

-2×(1) 2H₂O(g) ⟶ 2H₂(g) + O₂(g) ΔH = +483,6 kJ

-2×(5) 2H₂O(l) ⟶ 2H₂O(g) ΔH = +88.0 kJ

= <em>XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g)</em>

Where ΔH is:

ΔH = -639,1 kJ -369,2 kJ -356,9 kJ +483,6 kJ +88,0 kJ

<em>ΔH = -793,6 kJ</em>

I hope it helps!

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THE QUESTION:which letter in the diagram above represents a mountain range in the ocean floor  

A.Letter B  

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34kurt

Answer:

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Explanation:

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