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Ivan
3 years ago
12

The compressibility factor of any gas at a specific value of reduced temperature, T Tc, and reduced pressure, P Pc does not have

approximately the same value for all species. Select one: True False
Chemistry
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

False

Explanation:

According to principle of corresponding state, at reduced states or corresponding state, behavior of all gases are similar.

This principle is proposed by van der Waals.

In other words, all gases at same reduced temperature, reduced pressure and reduced volume deviate from ideal gas behavior to the same degree or have same compressibility factor.

Reduced quantities are defined as:

Reduced pressure P_R = \frac{P}{P_c}

Reduced temperature T_R = \frac{T}{T_c}

Reduced volume V_R = \frac{V}{V_c}

Where,

P_c = Critical pressure

V_c = Critical volume

T_c = Critical temperature

The compressibility factor (Z_c) at critical temperature is given by,

                                      Z_c=\frac{P_c V_c}{n_c k_B T_c}

Crtitical parameters (critical temperaures, critical pressure and critical volume) can be expressed in terms of van der Waals parameters a and b.

Principle of corresponding state can also be stated as gases at the same reduced pressure and reduced temperature have same reduced volume.

Hence, compressibility factor at reduced state will be same for all gase. so the given statement is false.

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Enter your answer in the provided box. On a certain winter day in Utah, the average atmospheric pressure is 718 torr. What is th
AnnZ [28]

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The correct answer is 0.047 mol/L

Explanation:

The atmospheric air is a mixture of gases. We can assume an ideal behavior of the gas and use the ideal gas equation:

PV= nRT

where P is the pressure, V is the volume, n is the number of moles, R is a constant (0.082 L.atm/K.mol) and T is the temperature in K.

We have to first convert the pressure from Torr to atm:

760 Torr= 1 atm

⇒ 718 Torr x 1 atm/760 Torr = 0.945 atm

Then, we convert the temperature from ºC to K:

0ºC = 273 K

⇒ -29ºC+273= 244 K

Finally, we introduce the data in the equation and calculate de densitiy, which is the moles per liters of gas (n/V):

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n/V = (0.945 atm)/(0.082 L.atm/K.mol x 244 K) = 0.047 mol/L

7 0
3 years ago
How many iron atoms are in 0.32 mol of Fe2031? 3.9x 1023 jron atoms O 3.9 iron atoms O 6.02 x 1023 iron atoms 1.9 x 1023 iron at
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Answer: 3.9\times 10^{23} iron atoms

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 molecule of [tex]Fe_2O_3 contains= 2 atoms of iron

1 mole of [tex]Fe_2O_3 contains=2\times 6.023\times 10^{23}=12.05\times 10^{23}  atoms of iron

thus 0.32 moles of Fe_2O_3 contains=\frac{12.05\times 10^{23}}{1}\times 0.32=3.9\times 10^{23}  atoms  of iron

Thus the sample would have 3.9\times 10^{23} iron atoms.

8 0
3 years ago
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