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DerKrebs [107]
3 years ago
9

I WILL GIVE 50 POINTS AND BRAINLIEST TO WHO EVER ANSWERS THIS RIGHT AND FAST!!! PLS!!!!

Chemistry
2 answers:
lyudmila [28]3 years ago
6 0

Answer: D

Explanation: I took the quiz! Module 04.06! Have a good day!

poizon [28]3 years ago
4 0

The answer is D

I took the test and I got this answer, it was correct :)

I don’t care if I get brainliest I just want to help

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Mazyrski [523]

Answer:

Diagram Z

Explanation:

A cell placed into a hypotonic solution will swell and expand until it eventually burst through a process known as cytolysis.

4 0
2 years ago
How To Calculate The Structure Ofan Element?
KATRIN_1 [288]

To calculate for the structure of an element, you need to have a solid analyzer such as an x ray diffractometer to determine the elements’ structure. It is hard to determine it without any help of instrument because of its size.

3 0
3 years ago
What elements are formed by stars having a mass greater than eight suns?
Hoochie [10]
An elements like helium and Boron are formed by stars having a mass of one to eight suns. The example elements that are formed by stars having a mass of one to eight suns are helium and boron. The stars normally turns into a white dwarf when the mass of the stars are less than 5 times the mass of the sun.
5 0
3 years ago
A toxicologist studying mustard gas, S(CH2CH2Cl)2, a blistering agent, prepares a mixture of 0.675 M SCl2and 0.973 M C2H4 and al
Musya8 [376]

Answer:

The value of K_p is 0.02495.

Explanation:

Initial concentration of SCL_2 gas = 0.675 M

Initial concentration of C_2H_4 gas = 0.973 M

Equilibrium concentration of mustard gas = 0.35 M

SCl_2 (g) + 2 C_2H_4 (g)\rightleftharpoons S(CH_2CH_2Cl)_2(g)

initially

0.675 M            0.973 M        0

At equilibrium ;

(0.675-0.35) M            (0.973-2 × 0.35) M        0.35 M

The equilibrium constant is given as :

K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}

=\frac{0.35 M}{(0.675-0.35) M\times ((0.973-2 × 0.35) M)^2}

K_c=14.45

The relation between K_p and K_c are :

K_p=K_c\times (RT)^{\Delta n}

where,

K_p = equilibrium constant at constant pressure = ?

K_c = equilibrium concentration constant =14.45

R = gas constant = 0.0821 L⋅atm/(K⋅mol)

T = temperature = 20.0°C =20.0 +273.15 K=293.15 K

\Delta n = change in the number of moles of gas = [(1) - (1 + 2)]=-2

Now put all the given values in the above relation, we get:

K_p=14.45\times (0.0821L.atm/K.mol\times 293.15 K)^{-2}

K_p=6.2\times 10^{4}

K_p=0.02495

The value of K_p is 0.02495.

7 0
3 years ago
2. (10 Points) If the experiment had continued with you adding an 8 kg weight to
vaieri [72.5K]

Answer: picture is work for # 1,2,4,5,7

Explanation: number 3: as the pressure in the volume decreases, the volume increases causing it to expand and eventually blow.

number 6: because the temperature and the amount of gas don’t change, these terms don’t appear in the equation. What Boyle’s law means is that the volume of a mass of gas is inversely proportional to its pressure. This linear relationship between pressure and volume means doubling the volume of a given mass of gas decreases its pressure by half.

hope this helps :))

4 0
3 years ago
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