Question

If a photon has a frequency of 1.15 × 1015 hertz, what is the energy of the photon? Given: Planck's constant is 6.63 × 10-34 joule·seconds.

Answer 1

5.82 x 10-49 joules7.62 x 10-19 joules8.77 x 10-12 joules1.09 x 10-12 joules  answer is b

Answer 2

Answer:

Energy of photon, $E=7.62\times 10^{-19}\ J$

Explanation:

It is given that,

The frequency of the photon, $\nu=1.15\times 10^{15}\ Hz$

Value of Planck's constant, $h=6.63\times 10^{-34}\ J-s$  

We have to find the energy of the photon. The energy of photon is given by the product of Planck's constant and the frequency of photon. It is given by :

$E=h\nu$

$E=6.63\times 10^{-34}\ J-s\times 1.15\times 10^{15}\ Hz$

$E=7.62\times 10^{-19}\ J$

Hence, this the required solution for the energy of the photon.