The velocity of a given wave remains the same while the wavelength increases. What happens to the frequency of the wave?

How do noise canceling headphones work?

postnew [5]

Answer:

B.) by interfering with sound waves

Explanation:

As we know that the interference of sound waves is of two types

1). constructive interference

2). destructive interference

now we know that constructive interference means the resultant intensity will be more than the intensity of interfering waves as here two waves are in same phase.

In destructive interference the resultant of two waves is given by the minimum resultant of the intensity as here the phase of two waves are opposite to each other.

So we will say that

$I = \sqrt{(I_1 + I_2 + 2\sqrt{I_1I_2}cos\theta)}$

here in case of noise cancelling headphones we know that the phase of noise is always made in opposite phase with the sound which is used to cancelled the noise.

This will reduce the noise and we will get a clear sound

5 0

3 years ago

Read 2 more answers

A wire is oriented along the x-axis. It is connected to two batteries, and a conventional current of 2.4 A runs through the wire

Deffense [45]

Answer:

$\vec{F}=0.40176 N \hat{k}$

Explanation:

To calculate the force we need to use this equation

$\vec{F}=\int\limits^L_0 {i(\vec{dl}\times\vec{B})}$

where L is the total length of the wire

So in this case the small element of current is

$\vec{dl} = dx \hat{i}$

Because x is the direction of the current flow.

As is said in the problem B is such that

$\vec{B} = B \hat{j} = 0.62\hat{j} [ T]$

so to use the equation above we first calculate the following cross product:

$\vec{dl}\times\vec{B}=dx \hat{i}\times B \hat{j} = Bdx\hat{k}$

so the force:

$F = \int\limits^L_0 {i(\vec{dl}\times\vec{B})}=\int\limits^L_0{iBdx\hat{k}}$

So here we use the fact that B=0 in any point of the x axis that is not $x^{'}=0.27 [m]$ , that means that we only need to do the integration between a very short distant behind the point $x^{'}=0.27 [m]$ and a very short distant after that point, meaning:

$\vec{F}= \lim_{h \to 0}{\int\limits^{x^{'}+h}_{x^{'}-h}{iBdx\hat{k}} }$

so is the same as evaluating $iBx$ at $x=x^{'}$

that is:

$2,4 A * 0,62 T * 0,27 m \hat{k}$

$2,4 A * 0,62 (\frac{Kg}{A s^{2}}) * 0,27 m \hat{k}$

$2,4*0,62*2,7 ( \frac{ kgm }{ s^{2} } ) \hat{k}$

$\vec{F}=0.40176 N \hat{k}$

5 0

3 years ago

You slide a slab of dielectric between the plates of a parallel-plate capacitor. As you do this, the potential difference betwee

LUCKY_DIMON [66]

Answer:

In this scenario adding the dielectric material in between the plates will have no effect on the capacitance of the plates since the voltage remains unchanged

Explanation:

Normally Introducing a dielectric into a capacitor decreases the electric field, which decreases the voltage, which increases the capacitance.

A capacitor with a dielectric stores the same charge as one without a dielectric, but at a lower voltage.

Voltage and capacitance are inversely proportional when charge is constant.

Now in this case the voltage remains the same hence the charges remain the same also because voltage is inversely proportional to capacitance

3 0

4 years ago

2. The convex mirror shown below has an object placed 15cm in front of it. An image is formed 35 cm

Elena-2011 [213]

Answer:

m = image distance/object distance

m=35/15=7/3

f=uv/(u+v)

35*15/(35+15)

f=10.5cm

4 0

3 years ago

Consider hitting a baseball with a bat. If we call the force on the bat against the ball the action force, identify the reaction

Nadya [2.5K]

Answer:

Explanation:

Action and reaction force are an integral part of third law of Newton . They are equal and opposite force - couple which act on two opposite objects. That is why they can not make a body in equilibrium.

In the given case, a bat is hit by a ball , at the point of contact , two equal and opposite forces emerge simultaneously , one acting on the ball and the other acting on the bat. As per the problem , force on the bat is called action . So the other force , that is force acting on the ball is called reaction force.

3 0

3 years ago