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VARVARA [1.3K]
2 years ago
6

The music is in ___meter? a.free timeb.duplec.tripled.quadruple​

Physics
2 answers:
KonstantinChe [14]2 years ago
6 0

Answer:

  • letter b. duple

Explanation:

  • anong fav subject mo hehe curious lang ako ehh pa brainly naman plsss
Rashid [163]2 years ago
4 0
D.quadruple is the answer
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If the motion of the particles in the room slow down, the temperature in the room would
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Answer:

Go down

Explanation:

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Heat and/or energy are transferred from one object to another if the objects have _________ temperature(s).
NISA [10]

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.....different temperatures

Explanation:

heat is a form of energy that is transfered from a body of high temperature to a body of low temperature....Cannot happen if the two bodies have the same temperature(thermal equilibrium)

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Differentiate between center of mass and center of gravity
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Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field. Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.

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3 years ago
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm . The explorer finds that
larisa86 [58]

Answer:

12.4 m/s²

Explanation:

L = length of the simple pendulum = 53 cm = 0.53 m

n = Number of full swing cycles = 99.0

t = Total time taken = 128 s

T = Time period of the pendulum

g = magnitude of gravitational acceleration on the planet

Time period of the pendulum is given as

T = \frac{t}{n}

T = \frac{128}{99}

T = 1.3 sec

Time period of the pendulum is also given as

T = 2\pi \sqrt{\frac{L}{g}}

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4 0
3 years ago
An object propelled upwards with an acceleration of 2.0 m / s ^ 2 is launched from rest. After 6 seconds the fuel runs out. Dete
dezoksy [38]

Answer:43.34 m

Explanation:

Given

acceleration(a)=2 m/s^2

Initial Velocity(u)=0 m/s

After 6 s fuel runs out

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v=u+at

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After this object will start moving under gravity

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s=0+\frac{2\times 6^2}{2}

s=36 m

After fuel run out distance traveled in upward direction is

v^2-u^2=2as_0

here v=0

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0-12^2=2(-9.8)(s)

s_0=\frac{144}{2\times 9.8}=7.34 m

s+s_0=36+7.34=43.34 m

7 0
3 years ago
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