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raketka [301]
3 years ago
12

The tortoise and the hare are having a race over a course of length 0.52 km. The tortoise crawls along at a constant 0.075 m/s w

hile the hare sprints along at a constant 16.7 m/s (when he is not sleeping). The race starts and the hare runs halfway to the finish line and decides to take a nap while the tortoise plods along. Waking from his nap, the hare sees that the tortoise has made so much progress that he might lose the race. He takes off and just catches up to the toroise at the finish line so that the race ends in a tie. Be careful with units.
How many hours did the hare sleep before waking up?
Physics
1 answer:
EastWind [94]3 years ago
3 0

Answer:the hare slept for 1 hr 55minutes.

Explanation: distance is changed to meters = 520m

Speed=distance/time

Speed of tortoise is 0.075m/s=520m/t

Crops multiplying t= 520/0.075 = 6933.3 seconds.

Speed for hare 16.7m/s =260m/t

ie 260m is half of the distance.

t =15.56seconds

Therefore the time slept by the hare = 6933.3- 15.56= 6917.74 seconds.

Converting to hours = 1hr. 55minutes is the time the hare slept.

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6 0
4 years ago
Read 2 more answers
Which of the following has the greatest mass?<br> A. star<br> B. moon<br> C. planet<br> D.galaxy
Rashid [163]

Answer: I think the answer is d

Explanation: sry if wrong

3 0
3 years ago
Now the proton at B is removed and replaced by a lithium nucleus, containing three protons and four neutrons. The proton at loca
Digiron [165]

Answer:

         F = 3 fo

Explanation:

The electric force is given by Coulomb's law

         F = k q₁ q₂ / r²

where k is the Coulomb constant and is equal to 8.99 109  

with the initial charge the force is  

        Fo = k q₁ q₂ / r²  

        Fo =k q₁ q₂ / r²

In this case it is indicated that charge 1 is changed by the lithium atom a = 3 P  

we substitute  

        F = k 3p p / r²      

        F = 3 (k p² / r²)  

        F = 3 fo

 

we see that the charge increases by three orders of magnitude

8 0
3 years ago
Por que el movimiento de un auto que recorre una pista circular ni es M.R.U.V​
tigry1 [53]

Answer:

Salta al contenido principal

Contenido principal

Movimiento rectilíneo uniforme (MRU)

Movimiento Rectilíneo

Movimiento rectilíneo uniforme (MRU)

Imagina que eres un astronauta en la Estación Espacial Internacional. Estás arreglando unos paneles solares averiados, cuando de pronto, al presionar, tu destornillador sale disparado de tus manos. Si no lo atrapas a tiempo, el destornillador estará viajando por el espacio en línea recta y a velocidad constante, a menos que algo se interponga en su camino. Esto sucede porque la herramienta se mueve con movimiento rectilíneo uniforme, o MRU.

Foto de la Estación Espacial Internacional

Foto de la Estación Espacial Internacional

Estación Epacial Internacional orbitando nuestro planeta. Créditos: International Space Station orbiting above earth de la National Reconnaissance Office.

El MRU se define el movimiento en el cual un objeto se desplaza en línea recta, en una sola dirección, recorriendo distancias iguales en el mismo intervalo de tiempo, manteniendo en todo su movimiento una velocidad constante y sin aceleración.

Recuerda que la velocidad es un vector, entonces, al ser constante, no varía ni su magnitud, ni su dirección de movimiento.

Condiciones del MRU

Para que un cuerpo esté en MRU, es necesario que se cumpla la siguiente relación:

t−t

0

x−x

0

Constante

Donde

xxx: es la posición en el espacio y

ttt: es el tiempo.

De esta condición, llegamos a la ecuación del MRU:

x = x_0 + v(t-t_0)x=x

0

+v(t−t

0

)x, equals, x, start subscript, 0, end subscript, plus, v, left parenthesis, t, minus, t, start subscript, 0, end subscript, right parenthesis

Donde:

\Large x_0x

0

x, start subscript, 0, end subscript: posición en el instante \Large t_0t

0

t, start subscript, 0, end subscript

\Large xxx: Posición en el instante \Large ttt

Esto quiere decir que si conocemos la posición x_0x

0

x, start subscript, 0, end subscript en el instante t_0t

0

t, start subscript, 0, end subscript y sabemos cuál es la de la velocidad vvv, podremos conocer la posición xxx en cualquier instante ttt.

¡No olvides fijarte bien en las unidades que utilizas y de convertirlas si es necesario!

Veamos un ejemplo:

Imagínate que has programado un carro robótico para que tenga una velocidad constante ¿Puedes calcular a qué distancia desde el punto de partida estará luego de 30\text{ s}30 s30, start text, space, s, end text?

Tienes los siguientes datos:

v

x

0

t

0

t

=10 m/s

=0 m

=0 s

=30 s

Explanation:

espero y esto te ayude

5 0
3 years ago
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