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snow_tiger [21]
3 years ago
6

What do I say when commenting on my result?

Physics
1 answer:
nevsk [136]3 years ago
8 0
Result for what exactly?
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Suppose your local apparent solar time is 11 am, and you have a clock that says it is noon in Greenwich. What is your longitude
jeyben [28]

The longitude based on the time difference is 15 degrees.

<h3>Longitude of complete rotation of the Earth</h3>

The longitude of a complete rotation of the earth in a 24 hours is calculated  as follows;

= \frac{360^0}{24} = 15^0 \ of \ longitude

<h3>Time difference</h3>

The time difference between the local apparent solar time and the Greenwich time is calculated as follows;

t = 12 pm \ - \ 11 am\\\\t = 1 \ hour

Since it is one hour time difference, the longitude is 15 degrees.

Learn more about Earth longitude here: brainly.com/question/1939015

5 0
2 years ago
If we warm a volume of air, it expands. Does it then follow that if we expand a volume of air, it warms? Explain.
Ivahew [28]

Answer:

nope don't think so

Explanation:

the heat causes the molecules to move faster therefore expanding in watever it the air is in

3 0
3 years ago
Read 2 more answers
Determine the magnitude of force F so that the resultant FR of the three forces is as small as possible.
Kamila [148]

Answer: FR=2.330kN

Explanation:

Write down x and y components.

Fx= FSin30°

Fy= FCos30°

Choose the forces acting up and right as positive.

∑(FR) =∑(Fx )

(FR) x= 5-Fsin30°= 5-0.5F

(FR) y= Fcos30°-4= 0.8660-F

Use Pythagoras theorem

F2R= √F2-11.93F+41

Differentiate both sides

2FRdFR/dF= 2F- 11.93

Set dFR/dF to 0

2F= 11.93

F= 5.964kN

Substitute value back into FR

FR= √F2(F square) - 11.93F + 41

FR=√(5.964)(5.964)-11.93(5.964)+41

FR= 2.330kN

The minimum force is 2.330kN

8 0
3 years ago
The gravitational force between the Sun (mass = 1.99 × 1030 kg) and Mercury (mass = 3.30 × 1023 kg) is 8.99 × 1021 N. How far is
Vlad [161]

Mercury is 35.98 million miles from the Sun.

4 0
3 years ago
Read 2 more answers
A car traveling 90 km/hr is 100 m behind a truck traveling 50 km/hr. How long will it take the car to reach the truck?
Ber [7]

v = speed of car = 90 km/h

u = speed of truck = 50 km/h

d = initial separation distance = 100 m = 0.1 km

They meet at time t such that

vt = d + ut

t(v - u) = d

t = d/(v - u) = (0.1 km) / [(90 - 50) km/h] = 0.0025 hours

8 0
3 years ago
Read 2 more answers
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