<h2>
Hello!</h2>
The answer is A. Chemical energy to heat energy to kinetic energy to electrical energy.
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Why?</h2>
Let's check the energy conversion given in the statement:
Chemical energy: Chemical energy is usually obtained from a natural resource combustion. For this particular case is the result of natural gas combustion.
Heat energy: Heat energy comes from chemical reactions such as natural gas combustions.
Kinetic energy: Kinetic energy is obtained by turbines transforming the pressurized steam on mechanical movement. Turbines are formed by a turbine that absorbs the heat energy to do mechanical work and transmit it to an output rotating shaft.
Electrical energy: Electrical energy is generated by gas turbines when the rotating output shaft is connected to an electrical generator. Electrical generators use mechanical energy to generate electrical energy by using electromagnetic induction. Electrical generators are basically formed by a rotor and a stator.
Have a nice day!
Answer:
The kinetic energy for both objects is the same.
Explanation:
While in other cases the kinetic energies of two objects that have different masses might be different depending on their velocities, in this case both the 3 kg book and 5 kg bowling ball have the same kinetic energy.
This is because kinetic energy is calculated using the formula: K = 1/2 * m * v^2, where m represents the mass and v represents the velocity of the object.
Since the book and the bowling ball are sitting still on the floor, their velocities are zero. Hence, when we plug in 0 for velocity into the equation for kinetic energy, we will get that the kinetic energy is 0 for the book and the bowling ball.
Hope this helps!
Answer:
i found something on a website that will help you
Explanation:
do you want me to send you it???
If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

Where | A | is the magnitude of the vector and
is the angle that it forms with the x axis in the opposite direction to the hands of the clock.
In this problem we know the value of Ax and Ay and we need the angle
.
Vector A is in the 4th quadrant
So:

So:

So:

= -47.28 ° +360° = 313 °
= 313 °
Option 4.