Answer:
the electric field is 42.8×10^6 N/C
Explanation:
let k be the coulomb constant, Q be the charge distribution , R be the radius of the disk and x be the distance from the center.
k = 8.98755×10^9 N×m^2/c^2
Q = 6.1×10^-6 C
R = 4.9×10^-2 m
x = 3.1×10^-3 m
0.0605 Kg m^2
In this case where we have find he moment of inertia of this object about an axis perpendicular to the x-y plane and passing through the origin, we can just add three moment of inertia's .
MOI= 0.25×0.3^2 + 0.35×0.4^2- 0.45×0.2^2
= 0.0605 Kg m^2