Consider a disk of radius 4.9 cm, having a uniformly distributed charge of +6.1 μC. The value of the Coulomb constant is 8.98755
x 10 N m2/C2 Compute the magnitude of the electric field at a point on the axis and 3.1 mm from the center Answer in units of N/C.
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Answer:
<h2>206.67N</h2>Explanation:
The sum of force along both components x and y is expressed as;
The magnitude of the net force which is also known as the resultant will be expressed as
To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.
Given the position of the object along the x-component to be x = 6t² − 4;
Similarly,
Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N
For an uniformly accelerated motion, we can write
where
is the acceleration of this motion, which in this problem is the gravitational acceleration, with a negative sign because it points downward, against the direction of the motion; h=0.540 m is the distance covered by the flea, and 
is the initial velocity.
At the maximum height, the velocity is zero, so
. Therefore we can solve to find :
where
At the maximum height, the velocity is zero, so