Answer:
a= 4.14 m/s²
Explanation:
We calculate the weight component parallel to the displacement of the block:
We define the x-axis in the direction of the inclined plane , 25° to the horizontal.
W= m*g : Total block weight
Wx= W*sen25°= m*g* sen25°
We apply Newton's second law :
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Problem development
We apply the formula (1) to calculate the acceleration of the block:
∑Fx = m*a
Wx = m*a
m*g* sen25° = m*a : We divide by m on both sides of the equation
g* sen25° = a
a = g* sen25° = 9.8* sen25° = 4.14 m/s²
The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus. The number of neutrons is equal to the difference between the mass number of the atom (M) and the atomic number. Therefore, it is true!
13.6/4^2 - (-13.6/3^2) = -13.6/16 + 13.6/9 = .66 eV<span>
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<span>Increased pressure to stop the movement. The brake reduces the acceleration of the engine. The brake absorbs energy at the wheels when it is applied to moving vehicles. It applies a counter torque to the engine. The friction force created by the break stops the vehicle.</span>
