Well they could go down a hill to gain more kinetic energy.
The time to distance ratio is 2.1:1 , making the first time 5 seconds, the first distance 18.9 m, and the second time 15 seconds. I hope this helps!
Answer:
y = 54.9 m
Explanation:
For this exercise we can use the relationship between the work of the friction force and mechanical energy.
Let's look for work
W = -fr d
The negative sign is because Lafourcade rubs always opposes the movement
On the inclined part, of Newton's second law
Y Axis
N - W cos θ = 0
The equation for the force of friction is
fr = μ N
fr = μ mg cos θ
We replace at work
W = - μ m g cos θ d
Mechanical energy in the lower part of the embankment
Em₀ = K = ½ m v²
The mechanical energy in the highest part, where it stopped
= U = m g y
W = ΔEm = - Em₀
- μ m g d cos θ = m g y - ½ m v²
Distance d and height (y) are related by trigonometry
sin θ = y / d
y = d sin θ
- μ m g d cos θ = m g d sin θ - ½ m v²
We calculate the distance traveled
d (g syn θ + μ g cos θ) = ½ v²
d = v²/2 g (sintea + myy cos tee)
d = 9.8 12.6 2/2 9.8 (sin16 + 0.128 cos 16)
d = 1555.85 /7.8145
d = 199.1 m
Let's use trigonometry to find the height
sin 16 = y / d
y = d sin 16
y = 199.1 sin 16
y = 54.9 m
<span>The
temperature at which the vapor pressure of a liquid equals the
environmental pressure surrounding the liquid is best defined as:
Boling Point
</span>
Answer:
7.99 × 10⁸ atoms
Explanation:
The diameter of Molybdenum atom is 418pm = 0.000000000418m
therefore to determine number of Mo Atoms that'll be required =
0.334 ÷ 0.000000000418 = 7.99 × 10⁸ atoms
Mass of one Mo atom = 1.59×10⁻²² g
Mass of 7.99 × 10⁸ atoms that'll be required = 1.59×10⁻²² × 7.99 × 10⁸ =
12.7041 × 10⁻¹³g.