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3 years ago

What is the kinetic energy of a 3-kilogram bali that is rolling at 2 meters per second

Physics

2 answers:

Rzqust [24]3 years ago

7 0

Answer:

Explanation:

simply apply kinetic energy definitoon:

$k = \frac{1}{2} mv {}^{2} = \frac{1}{2} 3 \times 2 {}^{2} = 6$

alex41 [277]3 years ago

3 0

6 jules

hope this helps

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(physical science) could someone please help me out with this lab? if i’m being honest i did the lab but i lost all of my work :

djverab [1.8K]

Explanation:

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2 years ago

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denpristay [2]

Answer:

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3 years ago

Two tuning forks of frequency 480 hz and 484 hz are struck simultaneously. what is the beat frequency resulting from the two sou

umka21 [38]

Ans: Beat frequency = $f_b$ = 4Hz

Explanation:
The beat frequency is equal to the absolute value of the difference in frequency of the two waves. In other words, the number of beats per second is equal to the difference in frequency. It is due to the destructive and constructive interference. According to this interference, sound will be soft or loud.

Hence. the formula is:
Beat frequency = $f_b = |f_2 - f_1|$

Since,
 $f_1 = 480Hz$
$f_2 = 484Hz$

Therefore,
Beat frequency = $f_b = |484 - 480|$

=> Beat frequency = $f_b = 4Hz$
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3 years ago

How much heat in joules is required to heat a 50 g sample of aluminum from 71 ∘f to 142 ∘f?

Vsevolod [243]

A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its ... How many joules of heat are needed to raise the temperature of 10.0 g of aluminum from 22°C to 55°C, if the specific heat of aluminum is o.90 J/g”C2 .

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3 years ago

An ordinary egg can be approximated as a 5.5-cm diameter sphere. The egg is initially at a uniform temperature of 8°C and is dro

kupik [55]

Answer:

a) $Q_{in} = 13.742\,kW$ , b) $\Delta S = 370.15\,\frac{kJ}{K}$

Explanation:

a) The heat transfered to the egg is computed by the First Law of Thermodynamics:

$Q_{in} +U_{sys,1} - U_{sys,2} = 0$

$Q_{in} = U_{sys,2} - U_{sys,1}$

$Q_{in} = \rho_{egg}\cdot \left(\frac{4\pi}{3}\cdot r^{3}\right)\cdot c \cdot (T_{2}-T_{1})$

$Q_{in} = \left(1020\,\frac{kg}{m^{3}}\right)\cdot \left(\frac{4\pi}{3}\right)\cdot (0.025\,m)^{3}\cdot \left(3.32\,\frac{kJ}{kg\cdot ^{\textdegree}C} \right)\cdot (70\,^{\textdegree}C - 8\,^{\textdegree}C)$

$Q_{in} = 13.742\,kW$

b) The amount of entropy generation is determined by the Second Law of Thermodynamics:

$\Delta S = \frac{Q_{in}}{T_{in}}$

$\Delta S = \frac{13.742\,kJ}{370.15\,K}$

$\Delta S = 370.15\,\frac{kJ}{K}$

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3 years ago