What is the magnitude of the electric field at the dot in the figure? (figure 1)
1 answer:
The magnitude of the electric field at the dot is : 10⁴ v/m
<h3>What is electric field?</h3>
Electric field is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.
Given that there are three equipotential lines with equal spacing,we will apply the the relationship between P.D and electric field
Determine the magnitude of the electric field at the dot
change in voltage = E .d
From equation ( 1 )
The magnitude of electric field will be given as
Hence we can conclude that The magnitude of the electric field at the dot is : 10⁴ v/m
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Answer:
145 m
Explanation:
Given:
Wavelength (λ) = 2.9 m
we know,
c = f × λ
where,
c = speed of light ; 3.0 x 10⁸ m/s
f = frequency
thus,
substituting the values in the equation we get,
f = 1.03 x 10⁸Hz
Now,
The time period (T) =
or
T = = 9.6 x 10⁻⁹ seconds
thus,
the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s
Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s
Now,
For radar to detect the object the pulse must hit the object and come back to the detector.
Hence, the shortest distance will be half the distance travelled by the pulse back and forth.
Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}
Thus, the minimum distance to target = = 145 m