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Mandarinka [93]
3 years ago
6

When hydrogens on an unsaturated fatty acid lie on the same side of the carbon-carbon double bond, a ____________ formation exis

ts?
Chemistry
1 answer:
dedylja [7]3 years ago
7 0
When hydrogen ................................... a CIS formation exist.
There are two types of formation which are possible in fatty acids, these are CIS and TRANS configurations.
A fat is described as a CIS fatty acid if its hydrogen atoms are lying on the same side of the carbon carbon double bonds. A fat is said to be a trans fatty acid, if the hydrogen atoms in its molecules are lying on the opposite sides of the carbon bonds.
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2. Suggest four ways in which the concentration of PH3 could be increased in an equilibrium described by the following equation:
Nesterboy [21]

Answer

  • increase in temperature
  • decrease in pressure
  • continuous removal of PH3
  • adding more of P into the system

Explanation:

        In the reaction   P4(g)+6H2(g) ⇌ 4PH3(g);

  • The effect of temperature on equilibrium has to do with the heat of reaction. Recall that for an endothermic reaction, heat is absorbed in the reaction, and the value of ΔH is positive. Thus, for an endothermic reaction, we can picture heat as being a reactant:

        heat+A⇌BΔH=+

  • Since the reaction is endothermic reaction, heat is a absorbed. Decreasing the temperature will shift the equilibrium to the left, while increasing the temperature will shift the equilibrium to the right forming more of PH3.
  • According to Le Chatelier’s principle, adding additional reactant to a system will shift the equilibrium to the right, towards the side of the products. In the same Way, reducing the concentration of the product will also shift equilibrium to the right continually forming PH3 as it is removed.

4 0
3 years ago
If 31.6 g of KMnO4 is dissolved in enough water to give 160 mL of solution, what is the molarity?
Zina [86]

Answer:

A. 1.25M

B. 19.98g

Explanation:

A. Data obtained from the question include the following:

Mass of KMnO4 = 31.6 g

Volume = 160 mL

Molarity =..?

We'll begin by calculating the number of mole KMnO4 in the solution. This is can be obtained as follow:

Mass of KMnO4 = 31.6 g

Molar mass of KMnO4 = 39 + 55 + (16x4) = 158g/mol

Number of mole of KMnO4 =..?

Mole = mass /Molar mass

Number of mole of KMnO4 = 31.6/158 = 0.2 mole

Now, we can obtain the molarity of the solution as follow:

Volume = 160 mL = 160/1000 = 0.16L

Mole of KMnO4 = 0.2 mole

Molarity = mole /Volume

Molarity = 0.2/0.16 = 1.25M

B. Data obtained from the question include the following:

Volume = 300mL

Molarity = 0.74 M

Mass of H2C2O4 =..?

First, we shall determine the number of mole H2C2O4. This is illustrated below:

Volume = 300mL = 300/1000 = 0.3L

Molarity = 0.74 M

Mole of H2C2O4 =?

Mole = Molarity x Volume

Mole of H2C2O4 = 0.74 x 0.3

Mole of H2C2O4 = 0.222 mole

Now, we can easily find the mass of H2C2O4 by converting 0.222 mole to grams as shown below:

Number of mole of H2C2O4 = 0.222 mole

Molar mass of H2C2O4 = (2x1) + (12x2) + (16x4) = 2 + 24 + 64 = 90g/mol

Mass of H2C2O4 =..?

Mass = mole x molar mass

Mass of H2C2O4 = 0.222 x 90

Mass of H2C2O4 = 19.98g

5 0
3 years ago
When is di- used in the name of a hydrocarbon?
harkovskaia [24]
Di- is used when you are naming organic compounds. If you have the same substituent repeated twice in the compund
For example: CH3-CH(CH3)-CH2-CH(CH3)-CH3
This will be named 2,4-dimethylpentane
6 0
3 years ago
What a hotspot mainly about like what's it's definition ?
shusha [124]
Small area or region with a relatively hot temperature in comparison to its surroundings.a very hot and dry place where a fire is likely to start, or where a fire has been burning.
7 0
4 years ago
What do you think will happen to the chipmunk population over the next five years(2001-2011)​
m_a_m_a [10]

Answer:they will out live us himans

Explanation:

7 0
3 years ago
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