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3 years ago

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The tables below show running hours of three printers that produce greeting cards and the total number of greeting cards produce

d over three weeks.
Printer B uses $15 in ink every hour. What is the ink cost for each card coming from printer B?

A. $0.30
B. $0.50
C. $1.00
D. $1.50

2 answers:

AysviL [449]3 years ago

8 0

<u>ANSWER</u>

The correct answer is A

<u>EXPLANATION</u>

To find the ink cost of each card coming from printer B, we need to find the total cost from printer B and the total number of cards printed by Printer B.

The total hours of all the three printers over the three weeks

$=40+45+55+50+50+30+45+40+60=415$

The total hours of printer B only

$=50+50+30=130$

Total number of cards produced over the three weeks

$=7950+7800+9600=25350$

We can use ratio and proportion to determine the total cards produce by printer B only.

$415:25350$

$130:x$

If less, more divides

$x=\frac{130\times 25350}{415} \approx7941$

Total cost of Printer B in 130 hours

$ $=130 \times 15=1950$

The ink cost

$=\frac{1950}{7941}$

$=0.2456$

$ $\approx 0.30$

to 2 decimal places

ella [17]3 years ago

3 0

Answer:

is A correct?

Step-by-step explanation:

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The picture above tap and tell me yes or no in order thank you :)

artcher [175]

Step-by-step explanation:

no,yes,no, d is probably yes I guess

4 0

2 years ago

Read 2 more answers

The regular price of a child's entry ticket to a water park is $8 less than that for an adult's. The park offers half off of all

valkas [14]

<span>194 = 1/2x + 2(x - 8)
194 = 1/2x + 2x - 16 = 5/2x - 16
5/2x = 194 + 16 = 210
5x = 210 x 2 = 420
x = 420/5 = 84

Therefore, the regular price of a child's ticket is $84 - $8 = $76.
</span>

3 0

3 years ago

PLEASE ANSWER QUICKLY ASAP <br>ANSWER QUESTION A

77julia77 [94]

Answer:

2934.46692

Step-by-step explanation:

if you need to round it,

hundrenths: 2,934.47

tenths: 2,934.5

Thousandths: 2,934.467

Hope this helps!

3 0

3 years ago

To solve y and x, I am adding a picture

Viktor [21]

Answer:

$x =\sqrt 5$

$y = \sqrt{5$

Step-by-step explanation:

Given

The attached triangle

Required

Solve for x

Considering angle 45 degrees, we have:

$\cos(45) = \frac{y}{\sqrt{10}}$ --- cosine formula i.e. adj/hyp

Solve for y

$y = \sqrt{10} * \cos(45)$

In radical form, we have:

$y = \sqrt{10} * \frac{1}{\sqrt 2}$

$y = \sqrt{10/2}$

$y = \sqrt{5$

To solve for x, we make use of Pythagoras theorem

$x^2 + y^2 = (\sqrt{10})^2$

$x^2 + y^2 =10$

Substitute for y

$x^2 + (\sqrt 5)^2 =10$

$x^2 + 5 =10$

Collect like terms

$x^2 =10-5$

$x^2= 5$

Solve for x

$x =\sqrt 5$

4 0

3 years ago

Describe lengths of three segments that could not be used to form a triangle. Segments with lengths of 5 in., 5 in., and ______

Vesna [10]

Answer:

$c = 11$

Step-by-step explanation:

Given

Let the three sides be a, b and c

Such that:

$a = b= 5$

Required

Find c such that a, b and c do not form a triangle

To do this, we make use of the following triangle inequality theorem

$a + b > c$

$a + c > b$

$b + c > a$

To get a valid triangle, the above inequalities must be true.

To get an invalid triangle, at least one must not be true.

Substitute: $a = b= 5$

$5 + 5 > c$ $===>$ $10 > c$

$5 + c > 5$ $===>$ $c > 5 - 5$ $===>$ $c > 0$

$5 + c > 5$ $===>$ $c > 5 - 5$ $===>$ $c > 0$

The results of the inequality is: $10 > c$ and $c > 0$

Rewrite as: $c > 0$ and $c < 10$

$0 < c < 10$

This means that, the values of c that make a valid triangle are 1 to 9 (inclusive)

Any value outside this range, cannot form a triangle

So, we can say:

$c = 11$ , since no options are given

8 0

2 years ago