If the brackets need to be a square term of the form (x+h)^2
then
just half the co-efficient of x term and square it.
So here it will be
(-6)/2 = -3
squaring it, (-3)^2 = 9
so 9 is what goes in the blank to make the bracket () of the form (x+h)^2
Answer:
- modulus: 3√2
- argument: -3π/4 (or 5π/4)
Step-by-step explanation:
The modulus is the magnitude of the complex number; the argument is its angle (usually in radians).
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<h3>rectangular form</h3>
The complex number can be cleared from the denominator by multiplying numerator and denominator by its conjugate:

<h3>polar form</h3>
The magnitude of this number is the root of the sum of the squares of the real and imaginary parts:
modulus = √((-3)² +(-3)²) = 3√2
The argument is the arctangent of the ratio of the imaginary part to the real part, taking quadrant into consideration.
arg = arctan(-3/-3) = -3π/4 or 5π/4 . . . . radians
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modulus∠argument = (3√2)∠(-3π/4)
Answer:
02 High Schools would be selected from the stratum with a percent-free-lunch value of 40 less than or equals x.
Step-by-step explanation:
As the sample size needed is 25 and total schools are 100 so this indicate 1 school in each 4 schools is to be selected. This is given as

Now as the schools with percent free lunch are 8 so now

So only 2 schools will be selected in this regard.
Multiply 2/5 by 2 to get 4/10
4/10 + 3/10 = 7/10