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lyudmila [28]
3 years ago
6

Emma jogs 2 miles along the beach in 1 3 of an hour. If she travels at a constant rate, how far will she jog in an hour? 1. Use

the known information to write a rate.
Mathematics
1 answer:
svp [43]3 years ago
4 0

Answer:oufonsrgonsrgnrsosgnsogwo0on93rhskgv oaoef

Step-by-step explanation:

iaeiuaefiaef ebf efa fcade emma jog 123e oefofoinsfnfsaefosefnhsfnalnfaogh

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A pole 9 feet tall is used to support a guy wire for a tower, which runs from the tower
STALIN [3.7K]

Answer:

42 feet

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2 years ago
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Please help fast with correct answer no guessing answer. Only answer if actually know the answer
lawyer [7]

Answer:

it is d inverse

Step-by-step explanation:

7 0
3 years ago
60% of Herbert's movies are adventure movies. He has 18 adventure movies. How many movies does Herbert have in all?
Vera_Pavlovna [14]
Data:
x (Number of movies) = ?


\frac{60}{100} *x = 18
0,6x = 18
x =  \frac{18}{0,6}
\boxed{x = 30}

Answer:
<span>Herbert have in all ?
30 movies</span>
5 0
3 years ago
Which of the following equations could be used to find the missing measurement in this triangle?
Kipish [7]
<span>the answer is 352 + 372 = a2</span>
4 0
3 years ago
Find the surface area of each figure to the nearest tenth.
Stells [14]
For the cylinder on the left-hand-side,

\bf \textit{surface area of a cylinder}\\\\&#10;S=2\pi r(h+r)\quad &#10;\begin{cases}&#10;r=radius\\&#10;h=height\\&#10;------\\&#10;h=10\\&#10;r=5&#10;\end{cases}\implies S=2\pi (5)(10+5)

now, for the triangular prism on the right-hand-side,

notice is really just 2 triangles and 3 rectangles, stacked  up to each other at the edges.

the triangles have a base of 4, and a height of 1.5.

the rectangle on the left and the one on the right is a 6x2.5 rectangle.

the rectangle at the bottom, is a 4x6 rectangle.

adding their areas, is the area of the prism,

\bf \stackrel{two~triangles}{2\left[\cfrac{1}{2}(4)(1.5)  \right]}+\stackrel{left-right~rectangles}{2(6\cdot 2.5)}+\stackrel{bottom~rectangle}{4\cdot 6}&#10;\\\\\\&#10;6~~+~~30~~+~~24
7 0
3 years ago
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