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dusya [7]
4 years ago
14

Which equations could you use the division property of equality to solve?

Mathematics
2 answers:
marysya [2.9K]4 years ago
8 0

Answer:

The answers are

2.35y = 4.70

4 = 10w

55x = 111

disa [49]4 years ago
3 0

Answer:

2.35y = 4.70

4 = 10w

55x = 111

Step-by-step explanation:

Hi, the division property of equality states that if we divide both sides of an equation by a non-zero number, the equality remains. (Both sides remain equal).

So, the equations that we have to use the division property of equality to solve are:

  • 2.35y = 4.70

Dividing both sides by 2.35:

2.35y /2.35= 4.70/2.35

y= 2

  • 4 = 10w

4/10=10w/10

0.4=w

  • 55x = 111

55x/55 =111/55

x = 111/55

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Answer:

Length = 7

Width = 15

Step-by-step explanation:

L= x

W= x-8

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SOMEONE HELP PLZ !! 74 points lol and brainliest .
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A cylinder has a height of 8.1 inches and circular base with a diameter of 2.7 inches. The cylinder contains 3 green spheres, ea
klasskru [66]

Answer:

A point is chosen at random inside the cylinder, then probability the point belongs outside of the spheres is 0.25

Step-by-step explanation:

Let's find volume of the cylinder and volume of the three spheres.

Volume of cylinder =\pi r^{2} h

Volume of sphere =\frac{4}{3} \pi r^{3}

Now, r =2.7

h=8.1

Find volume of each shape.

Volume of cylinder =\pi (2.7)^{2} (8.1)

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Now, volume of 3 spheres =3*\frac{4}{3} *\pi *(2.7)^{3}

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Now, p(E)=\frac{Outcomes favorable to event E}{Total number of outcomes}

So, Probability of point is chosen at random inside the cylinder which belongs outside of the spheres  is

                  \frac{78.732\pi -59.049\pi }{78.732\pi }

Let's simplify them

             0.25

A point is chosen at random inside the cylinder, then probability the point belongs outside of the spheres is 0.25

6 0
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Step-by-step explanation:

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(brainliest if this is correct for you)

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