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NikAS [45]
3 years ago
5

What two numbers add to negative 9 but multiply to 24

Mathematics
1 answer:
miss Akunina [59]3 years ago
3 0
There aren't any numbers that add to 24 but multiply to 9. But you can still factorise - remember, you only need to get numbers that add up to the middle number if the coefficient of y^2 is 1. That means if you just have y^2, not 2y^2 or 3y^2 or 16y^2 like we do here. 

<span>16y^2+24y+9 = (4y+3)^2</span>
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Which is equivalent to (4 × 2) × 7?<br><br> 6 × 7<br> 8 + 5<br> 8 × 7<br> 4 × (2 + 7)
d1i1m1o1n [39]

Answer:

8 × 7

Step-by-step explanation:

(4 × 2) × 7

We can multiply what is inside the parentheses

(8) × 7

5 0
3 years ago
Read 2 more answers
Solve the following equation for y. Y= 2y+4y-3=27
sammy [17]

Answer:

2y + 4y - 3 = 27 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 6y = 27 + 3 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 6y = 30 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: y =  \frac{30}{6}  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: y = 5

4 0
3 years ago
What is (f ° g)(2) and (g ° f)(2) with the set of points f: {(0,4), (1,2), (2,0), (3,2), (4,4)} and g: {(0,4), (1,3), (2,2), (3,
kumpel [21]

Answer:

\large\boxed{(f\circ g)(2)=0}\\\boxed{(g\circ f)(2)=4}

Step-by-step explanation:

f:\{(0,4), (1,2), \underline{(2,0)}, (3,2), (4,4)\}\\\\g:\{\underline{(0,4)}, (1,3), \underline{(2,2)}, (3,1), (4,0)\}\\\\(f\circ g)(x)=f\bigg(g(x)\bigg)\\\\g(2)=2\qquad/from\ (2,2)/\\f\bigg(g(2)\bigg)=f(2)=0\qquad/from\ (2,0)/\\\\(g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(2)=0\qquad/from\ (2,0)/\\g\bigg(f(2)\bigg)=g(0)=4\qquad/from\ (0,4)/

7 0
3 years ago
MN and KL are parallel. If JM = 6, MK = 12, and LN = 18, what is NJ?
Galina-37 [17]
6/12=X/18
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Answer: NJ=9
5 0
4 years ago
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