12+34 = 46
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Find the volumen of the semisphere and subtract the volumes of the two cylinders
1) Volume of the semisphere:
[1/2] (4/3)π(r^3) =[ 2π(1.5m)^3 ]/3 = 7.0686 m^3
2) Volumen of the cylinders:π(r^2)h
a) π(0.75/2m)^2 (1.75m) = 0.7731 m^3
b) π(1/2m)^2 (1.25m) = 0.9818 m^3
3) 7.0686 m^3 - 0.7731 m^3 - 0.9818m^3 = 5.3137 m^3
Answer: 5.3 m^3
Answer:
V = $3.50t + $90.5....
Step-by-step explanation:
V(t) is a function of t that expresses the value in year 2000+t.
We know that the increase is $3.50 times t.
So,
V(t) = $3.50t + c
where c is the constant.
V(15) = $3.50 (15) + c = $143 [t=15 as mentioned in the question]
and therefore
c = $143 - $3.50 (15)
c= $143 - $52.50
c= $90.5
Now we got the value of c. We can write the equation as
V = $3.50t + $90.5....
An equivalent ratio would be 7:10 or 70:100 or 42:60 and so on...
The vertex of f(x)=-x2+4x-8 is (2, -4)
