we conclude that the point on this line that is apparent from the given equation is (-6, 6)
<h3>
Which point is on the line, only by looking at the equation?</h3>
Remember that a general linear equation in slope-intercept form is:
y = a*x + b
Where a is the slope.
Here we have the linear equation:
y - 6= (-23)*(x + 6)
Now, for a linear equation with a slope a and a point (h, k), the point slope form of the linear equation is:
(y - k) = a*(x - h)
Now we can compare that general form with our equation, we will get:
(y - k) = a*(x - h)
(y - 6) = (-23)*(x + 6)
Then we have: k = 6 and h = -6.
Thus, we conclude that the point on this line that is apparent from the given equation is (-6, 6).
If you want to learn more about linear equations:
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It is written as 35% or 0.35
Hope this helps!! :)
For this case we have the following expression:
We have to:
Rewriting the expression and simplifying we have:
Answer:
Answer:
13
Step-by-step explanation:
Since OCB forms a right triangle, you can find the length of side OB and therefore the radius by simply using the pythagorean theorem. The first step is to note that, since AB=24 and OC bisects that, that both CB and AC have length 12. Therefore, the radius is 
. Hope this helps!
Answer:
M=4
Step-by-step explanation:
29-25=4
M to the second = 16
16 + 9 = 25
That’s where the 25 comes from
Using the socratyne theorem this problem is easily solved as you see above.
With the 25, m = 4
