3. The set below only contains which types of

Jupiter has a mass of 1,898,000,000,000,000,000,000,000,000 kg. How would

Natasha2012 [34]

Answer:

B.1.898^27 kg

Explanation:

4 0

4 years ago

Which statement best describes Cleo's mistake? Light travels through air and water in angled, scattered paths. Light does not ch

pashok25 [27]

<u>The question</u> (obtained from the internet);

Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, speeds up, and bends towards the normal

Answer:

The statement that best describes Cleo's mistake is;

Light slows down when it moves from air into water

Explanation:

The question;

Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, speeds up, and bends towards the normal

The speed of light in water = 225,000 km/s

The speed of light in air = 299,702,547 m/s

The speed of light in vacuum = 299,792,458 m/s

Therefore, light slows down when it moves from a less dense medium to a denser medium

Light moves closer (bends) towards the normal when it moves from air into water. Light therefore, changes direction, and light moves in straight path which is known as rectilinear motion

Therefore, the statement that describes Cleo's mistake is that light actually slows down when it moves from air into water.

5 0

3 years ago

Can someone help me with one question? <br><br> “Do cells in the body help you grow?”

noname [10]

Body tissues grow by increasing the number of cells that make them up. Cells in many tissues in the body divide and grow very quickly between conception and adulthood.

5 0

3 years ago

Read 2 more answers

Compare these two collisions of a PE student with a wall.

Stolb23 [73]

1) The variable that is different in the two cases is $\Delta t$ , the duration of the collision

2) The change in momentum is the same in the two cases

3) The impulse is the same in the two cases

4) Case B will experience a greater force

Explanation:

1)

The variable that is different in the two cases is $\Delta t$ , the duration of the collision.

In fact, in the first case the wall is padded: this means that the collision will be "softer" and therefore will last longer, so the duration of the collision, $\Delta t$ , will be larger.

In the second case instead, the wall is unpadded: this means that the collision is "harder" and so it will last less time, therefore the duration of the collision $\Delta t$ will be smaller.

2)

The change in momentum in the two cases is the same.

In fact, the change in momentum is given by:

$\Delta p = m(v-u)$

where:

m is the mass of the student

u is the initial velocity

v is the final velocity

In both cases, we have:

m = 75 kg

u = 8 m/s

v = 0 (they both comes to rest)

Therefore, the change in momentum is

$\Delta p = (75)(0-8)=-600 kg m/s$

3)

The impulse in the two cases is the same.

In fact, impulse is defined as the product of force applied, F, and duration of the collision, $\Delta t$ :

$J=F \Delta t$

However, the force can be rewritten as product of mass (m) and acceleration (a), according to Newton's second law:

$F=ma$

So the impulse is

$J=ma\Delta t$

The acceleration can be rewritten as rate of change of velocity:

$a=\frac{\Delta v}{\Delta t}$

So the impulse becomes

$J=m\frac{\Delta v}{\Delta t}\Delta t = m\Delta v$

So, the impulse is equal to the change in momentum: and since in the two cases the change in momentum is the same, the impulse is the same as well.

4)

The force in the collision is related to the impulse by

$J=F\Delta t$

where

J is the impulse

F is the force

$\Delta t$ is the duration of the collision

The equation can be rewritten as

$F=\frac{J}{\Delta t}$

In the two situations described in the problem (A and B), we already said that the impulse is the same (because the change in momentum is the same). However, in case A (padded wall) the time $\Delta t$ is longer, while in case B (unpadded wall) the time $\Delta t$ is shorter: since the force F is inversely proportional to the duration of the collision, this means that in case B the student will experience a greatest force compared to case A.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

3 0

4 years ago

A clock battery wears out after moving 10,400 C of charge through the clock at a rate of 0.530 mA. (a) How long (in s) did the c

Sati [7]

Answer:

Explanation:

Given that:

Charge Q = 10400 C

current I = 0.530 mA

From our previous knowledge, we know that charge Q can be expressed as:

Q = I×t

where

I = current and t = time

∴

replacing our values

10400 = (0.530×10⁻³) t

t = 10400/(0.530×10⁻³)

t = 19622641.51 seconds

However, the required flow of electrons per seconds can be calculated by using the formula:

number of electrons/second = current (I)/ charge on electron

= (0.530×10⁻³)/(1.6×10⁻¹⁹)

= 3.3125×10¹⁵ electrons

7 0

3 years ago