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icang [17]
3 years ago
11

Which statement best describes Cleo's mistake? Light travels through air and water in angled, scattered paths. Light does not ch

ange direction when it moves from air into water. Light slows down when it moves from air into water. Light bends away from the normal when it moves from air into water.
Physics
1 answer:
pashok25 [27]3 years ago
5 0

<u>The question</u> (obtained from the internet);

Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, speeds up, and bends towards the normal

Answer:

The statement that best describes Cleo's mistake is;

Light slows down when it moves from air into water

Explanation:

The question;

Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, speeds up, and bends towards the normal

The speed of light in water = 225,000 km/s

The speed of light in air = 299,702,547 m/s

The speed of light in vacuum = 299,792,458 m/s

Therefore, light slows down when it moves from a less dense medium to a denser medium

Light moves closer (bends) towards the normal when it moves from air into water. Light therefore, changes direction, and light moves in straight path which is known as rectilinear motion

Therefore, the statement that describes Cleo's mistake is that light actually slows down when it moves from air into water.

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The molecule that functions as the reducing agent (electron donor) in a redox or oxidation-reduction reaction _____. Group of an
Elina [12.6K]

Answer:

b) loses electrons and loses potential energy

4 0
4 years ago
Jacob is traveling at 5.00 m/s North. Jacob throws a ball with a velocity of 5.00 m/s South. Jacob throws the ball from a height
Nataly [62]

Answer:t=0.54 s

Explanation:

Given

Jacob is traveling 5 m/s in North direction

Jacob throw a ball with a in south direction with a velocity of 5 m/s

Ball is thrown in opposite direction of motion of car therefore it seems as if it is dropped from car as its net horizontal velocity is 5-5=0

Time taken by ball to reach ground

s=ut+\frac{gt^2}{2}

1.45=0+\frac{9.81\times t^2}{2}

t^2=frac{2\times 1.45}{9.81}

t=0.54 s

Motion of ball will be straight line

3 0
4 years ago
On a warm, balmy summer day you decide to relax by watching the latest building renovation in your neighborhood. You notice that
liq [111]

Answer:

B) both the amplitude of the motion and the weight of the ball

Explanation:

Time period of a pendulum is given by

T=2\pi \sqrt{\dfrac{L}{g}}

where,

L = Length of pendulum

g = Acceleration due to gravity

The system here is similar to a simple pendulum

It can be seen that the time period depends on L and g.

Amplitude and weight are the factors that do not determine the time period.

Hence, the answer is B) both the amplitude of the motion and the weight of the ball

8 0
3 years ago
A runner of mass 53.0 kg runs around the edge of a horizontal turntable mounted on a vertical, frictionless axis through its cen
const2013 [10]

Answer:

0.336 rad/s

Explanation:

\omega_1 = Angular speed of the turntable = -0.2 rad/s

R = Radius of turntable = 2.9 m

I = Moment of inertia of turntable = 76\ kgm^2

M = Mass of turn table = 53 kg

v_1 = Magnitude of the runner's velocity relative to the earth  = 3.6 m/s

As the momentum in the system is conserved we have

Mv_1R+I\omega_1=(I + MR^2)\omega_2\\\Rightarrow \omega_2=\dfrac{Mv_1R+I\omega_1}{I + MR^2}\\\Rightarrow \omega_2=\dfrac{53\times 3.6-76\times 0.2}{76+53\times 2.9^2}\\\Rightarrow \omega_2=0.336\ rad/s

The angular velocity of the system if the runner comes to rest relative to the turntable which is the required answer is 0.336 rad/s

4 0
3 years ago
How much ke is possessed by a 100kg running forward at 4.0 m/s ?
Anvisha [2.4K]
KE = 1/2mv²
      = 1/2(100)(4.0²)
KE = 800 J

hope this helps :)

7 0
4 years ago
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