All categories

3 years ago

Explain what causes spring and neap tides, and identify

Physics

2 answers:

elena-14-01-66 [18.8K]3 years ago

5 0

Answer:

Spring tides occur when the moon is full or new. Earth, the moon, and the Sun are in a line. The moon’s gravity and the Sun’s gravity pull Earth’s crust and ocean water. This causes tides to be higher than normal. At neap tide, the moon and the Sun are at right angles to each other. This happens during the first and third quarters of the lunar cycle. At neap tide, the Sun’s gravity and the moon’s gravity are balanced. High tides are lower; low tides are higher.

Explanation:

Just did the quiz.

Elodia [21]3 years ago

3 0

this is the sample Answer: Spring tides occur when the moon is full or new. Earth, the moon, and the Sun are in a line. The moon’s gravity and the Sun’s gravity pull Earth’s crust and ocean water. This causes tides to be higher than normal. At neap tide, the moon and the Sun are at right angles to each other. This happens during the first and third quarters of the lunar cycle. At neap tide, the Sun’s gravity and the moon’s gravity are balanced. High tides are lower; low tides are higher.

Explanation:

just did the assament

You might be interested in

PLZZZZZZ HELP 50 POINTS Directions

Dmitrij [34]

Hey! Here's a a structure of a sample lab report:

<h2>Summary of Lab (SUBJECT)</h2>

Question(s) we are trying to answer:

Write question(s) here.

Add observations and/or previous experiments.

HYPOTHESIS

prediction
solution
replicable proposed solution
references (in)dependent variable(s)
etc

MATERIALS

Make a list of all materials used in the lab.

PROCEDURE

Write a detailed, step-by-step list (or paragraph in list format) that explains what you did in the lab.

It should be written so that somebody who's never done this can carry it out. Describe safety concerns.

It helps to have somebody test it out.

Results

Describe what happened!

Should include all data, tables, et cetera.

Label correctly!

Conclusion

Answer the following question:

Do my results support or oppose my hypothesis?

Explain why you chose what you did. Make sure it's UNBIASED.

Discuss errors.

Close out in the end.

5 0

2 years ago

Relative velocity.....Please help....

Romashka [77]

Answer:

3. Usinθ

Explanation:

The vertical component of velocity of any object reaching maximum height is 0 and the horizontal component of velocity of any object in flight remains constant.

Therefore the horizontal component of velocity is Ucosθ for both objects at any given time.

At maximum height A is having 0 vertical velocity but B which just starting its flight is having Usinθ as its vetical component of velocity.

Velocity of B relative to A = Velocity of B - Velocity of A

As velocity can be resolved to components,( to simplify the sum )

Horizontal component of velocity of B relative to A = Horizontal component of velocity of B - Horizontal component of velocity of A

which is 3. Usinθ

5 0

2 years ago

A 17,000-kg airplane lands with a speed of 82 m/s on a stationary aircraft carrier deck that is 115 m long. find the work done b

zepelin [54]

In physics, a force is said to do work if, when acting, there is a displacement of the point of application in the direction of the force. Nonconservative force for this question refers to FRICTIONAL force. 

By conservation of energy, 

Work done by Frictional force = Kinetic energy = 1/2(17000)(82)^2 = 57MJ

3 0

3 years ago

What happens when the kinetic energy of molecules increases so much that electrons are released by the atoms, creating a swirlin

gizmo_the_mogwai [7]

The "gas" is ionized and may correctly be described as a fourth state of matter - a plasma - rather than a gas. Both a gas and a plasma would expand indefinitely if not contained somehow but the ionized particles of a plasma could be controlled electromagnetically whereas a gas could not. A typical plasma is contained in an illuminated neon sign.

5 0

2 years ago

A thin block of soft wood with a mass of 0.072 kg rests on a horizontal frictionless surface. A bullet with a mass of 4.67 g is

Olegator [25]

Answer:

366.90149 m/s

923.821735 J

324.734 J

Initial Kinetic energy > Final kinetic energy

Explanation:

$m_1$ = Mass of block = 0.072 kg

$m_2$ = Mass of bullet = 4.67 g

$u_1$ = Initial Velocity of block = 0

$u_2$ = Initial Velocity of bullet = 629 m/s

$v_1$ = Final Velocity of block = 17 m/s

$v_2$ = Final Velocity of bullet

In this system the linear momentum is conserved

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\\\Rightarrow v_2=\frac{m_{1}u_{1}+m_{2}u_{2}-m_1v_1}{m_2}\\\Rightarrow v_2=\frac{0.072\times 0+4.67\times 10^{-3}\times 629-0.072\times 17}{4.67\times 10^{-3}}\\\Rightarrow v_2=366.90149\ m/s$

Final Velocity of bullet is 366.90149 m/s

The initial kinetic energy

$K_i=\frac{1}{2}m_2u_2^2\\\Rightarrow K_i=\frac{1}{2}4.67\times 10^{-3}\times 629^2\\\Rightarrow K_i=923.821735\ J$

The final kinetic energy

$K_f=\frac{1}{2}m_2v_2^2+\frac{1}{2}m_1v_1^2\\\Rightarrow K_f=\frac{1}{2}4.67\times 10^{-3}\times 366.90149^2+\frac{1}{2}0.072\times 17^2\\\Rightarrow K_f=324.734\ J$

Initial Kinetic energy > Final kinetic energy

3 0

3 years ago