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stiv31 [10]
3 years ago
13

Can someone help me with one question? “Do cells in the body help you grow?”

Physics
2 answers:
Gnoma [55]3 years ago
7 0

Answer: Body tissues grow by increasing the number of cells that make them up. Cells in many tissues in the body divide and grow very quickly between conception and adulthood.              yes

Explanation:

noname [10]3 years ago
5 0

Body tissues grow by increasing the number of cells that make them up. Cells in many tissues in the body divide and grow very quickly between conception and adulthood.
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Despite their name, standing waves actually do cause the medium to move
Gemiola [76]

Answer:

true

Explanation:

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3 years ago
ayo 20 m long is heated from a temperature of 5 degree celsius to 55 degree celsius if the change in length is 0.020 m calculate
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Answer:2 x 10^-5K^-1

Explanation:

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6 0
3 years ago
The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the ________ of a photon with a wavelength of ________ nm
Colt1911 [192]
The energy levels of the hydrogen atom are quantized and their energy is given by the approximated formula
E=-  \frac{13.6}{n^2} [eV]
where n is the number of the level.

In the transition from n=2 to n=6, the variation of energy is
\Delta E=E(n=6)-E(n=2)=-13.6 ( \frac{1}{6^2}- \frac{1}{2^2}  )[eV]=3.02 eV
Since this variation is positive, it means that the system has gained energy, so it must have absorbed a photon.

The energy of photon absorbed is equal to this \Delta E. Converting it into Joule,
\Delta E=3.02 eV=4.84 \cdot 10^{-19}J
The energy of the photon is
E=hf
where h is the Planck constant while f is its frequency. Writing \Delta E=hf, we can write the frequency f of the photon:
f= \frac{\Delta E}{h}= \frac{4.84 \cdot 10^{-19}J}{6.63 \cdot 10^{-34}m^2 kg/s}=7.29 \cdot 10^{14}Hz

The photon travels at the speed of light, c=3 \cdot 10^8 m/s, so its wavelength is
\lambda =  \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{7.29 \cdot 10^{14}Hz}=4.11 \cdot 10^{-7}m=411 nm

So, the initial sentence can be completed as:
The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the "absorption" of a photon with a wavelength of "411" nm.
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