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Fiesta28 [93]
3 years ago
12

Diedre drew a quadrilateral with 4 right Angles and opposite sides of the same length. Name all the kinds of polygons that could

be Diedre's quadrilateral.
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

The answer to the question is

The kinds of polygons that could be Diedre's quadrilateral are rectangle and square

Step-by-step explanation:

We  note the conditions of the polygon as thus

Number of sides = 4, Which include trapezoid, square, rectangle

Size of angles = 90 ° which eliminates trapezoid

Sizes of opposite sides = Equal opposite sides, includes square and rectangle

With the above we conclude that the possible polygons in Diedre's quadrilateral are rectangle and square

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Irina-Kira [14]
In order to find the equation of a line, you would have to use the equation y=mx+b. 

First, find the slope: \frac{y_{2}- y_{1} }{x_{2} x_{1} }
There is (1,8) and (2, 16) so plug that in 16-8/2-1 = 8. That's your slope! (Or the m)

Next in order to find b, you have to plug in a point:
y=8x+b
Take (1,8) and plug it in for x and y:
8=8(1)+b
b=0
Your y intercept is 0 (which you can also see on the graph)

So your answer is: y=8x
7 0
3 years ago
Write the set builder notation {8}
timofeeve [1]

Step-by-step explanation:

\{8 \} =  \{x : x = n, \: n \in \:N, \:   \: 7 < n > 9 \: \}

5 0
3 years ago
Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22. (Past studies have revealed that onl
Alex17521 [72]

Answer:

B. no, it is not low enough

A. no, it is not low enough

Step-by-step explanation:

Given that Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22.

Prob for  a random person booked arrive for flight = 0.86

No of persons who books and arrive for flight, X is binomial, since there are two outcomes and each person is independent of the other

The probability that if Air-USA books 24 persons, not enough seats will be available

= P(X=23)+P(x=24)

= 0.1315

B. no, it is not low enough

-------------------------------

The prob we got is >10% also

A. no, it is not low enough

7 0
3 years ago
Can anyone help me I don’t understand plz
Citrus2011 [14]

There we have an information of two functions g(t)\,  and \, h(t)

Using this two functions g(t)\,  and \, h(t), we need to find the composition of functions (h\circ g)(t).

The composition of two functions h and g is the new function , by performing g first and then performing h.

(h\circ g)(t)=h(g(t))

g(t)=3(t+1)

h(t)=2t

Composition of h and g (t) = (h\circ g)(t)

=h(g(t))

First plugin the value of g(t)=3(t+1)

h(g(t))=h(3(t+1))

=h(3t+3)

We know that h(t)=2t, we need to find h(3t+3),

That is, to replace t by 3t+3,

=2(3t+3)

Now distribute 2 into 3t+3,

=6t+6

Now plug in t=-6,

h(g(-6))=6(-6)+6

=-36+6 \\ =-30

Thus the solution is (D). h(g(-6))=-30.

5 0
3 years ago
Read 2 more answers
Can someone help with this question please
nirvana33 [79]

4×4=16


(8×4)4=128


(7×4)÷2=14

14×4=56


16+128+56=200


Ans: 200

6 0
3 years ago
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