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N76 [4]
3 years ago
7

Which does a reference point provide? Check all that apply. a position from which to measure future distance a set of standard u

nits for measuring displacement a standard method for evaluating variables a method for determining the speed of an object a way to detect an object’s motion
Physics
2 answers:
Ad libitum [116K]3 years ago
6 0

Answer:1, 2, and 5.

Explanation:

A position from which to measure future distance

A set of standard units for measuring displacement

A way to detect an objects motion

Natalka [10]3 years ago
3 0

A reference point provides a way to detect an objects movement.

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7 0
3 years ago
intial velocity is 45km/h, final velocity is 0, time taken is 3 seconds,calculate the retradation of the vehicle and distance tr
V125BC [204]

Answer:

v= u+at

0=45×1000×60×60+3a

_3a=16200045

a=5400015m per sec

4 0
3 years ago
Read 2 more answers
A ball is thrown directly downward with an initial speed of 7.95 m/s, from a height of 29.0 m. After what time interval does it
Y_Kistochka [10]

Answer: after 1.75 seconds

Explanation:

The only force acting on the ball is the gravitational force, so the acceleration will be:

a = -9.8 m/s^2

the velocity can be obtained by integrating over time:

v = -9.8m/s^2*t + v0

where v0 is the initial velocity; v0 = -7.95 m/s.

v = -9.8m/s^2*t - 7.95 m/s.

For the position we integrate again:

p = -4.9m/s^2*t^2 - 7.95 m/s*t + p0

where p0 is the initial position: p0 = 29m

p =  -4.9m/s^2*t^2 - 7.95 m/s*t + 29m

Now we want to find the time such that the position is equal to zero:

0 = -4.9m/s^2*t^2 - 7.95 m/s*t + 29m

Then we solve the Bhaskara's equation:

t = \frac{7.95 +- \sqrt{7.95^2 +4*4.9*29} }{-2*4.9} = \frac{7.95 +- 25.1}{9.8}

Then the solutions are:

t = (7.95 + 25.1)/(-9.8) = -3.37s

t = (7.95 - 25.1)/(-9.8) = 1.75s

We need the positive time, then the correct answer is 1.75s

4 0
4 years ago
A racecar traveling at a velocity of 18.5 m/s, accelerates at a rate of 2.47 m/s2 and covers a distance of 79.78 m. Determine th
Vesna [10]

Answer:

The final velocity of the race car is 27.14 m/s

Explanation:

Given;

initial velocity of the race car, u = 18.5 m/s

acceleration of the race car, a = 2.47 m/s²

distance covered by the race car, s = 79.78 m

Apply the following kinematic equation to determine the final velocity of the race car.

v² = u² + 2as

v² = (18.5)² + 2(2.47)(79.78)

v² = 736.363

v = √736.363

v = 27.14 m/s

Therefore, the final velocity of the racecar is 27.14 m/s

4 0
4 years ago
A bird has a kinetic energy of 3 J and a potential energy of 25 J. What is the mechanical energy of the bird?
Ahat [919]

Answer:

28 J

Explanation:

Mechanical energy is the sum of kinetic and potential energy in an object that is used to do work. In other words, it is energy in an object due to its motion or position, or both.

In physics, mechanical energy (Emech) is the energy associated with the motion and position of an object usually in some force field.

Therefore:

ME = KE + PE = 25 + 3 = 28 J

8 0
3 years ago
Read 2 more answers
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