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3 years ago

Who was martin Luther king and how is he celebrite

Chemistry

1 answer:

Anit [1.1K]3 years ago

5 0

Answer: martin luther king jr

Explanation: He led peaceful protests against the discrimination that the people of the United State did against African American men, women, and children. He was a celebrity due to his have "I a dream speech" that he said in front of the lincoln memorial. Plus he didn't approve of violence when trying to protest African American rights.

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Explain why the solutions of SbCl3(aq) in our lab also contain HCl. Why would adding a few drops of this solution to 300 mL of w

IRISSAK [1]

Answer:

Here's what I get

Explanation:

SbCl₃ reacts with water to form slightly soluble antimony oxychloride.

SbCl₃(aq) +H₂O(ℓ) ⇌ SbOCl(s) + 2HCl(aq)

Your observation is an example of Le Châtelier's Principle in action,

The SbCl₃(aq) in your lab has enough HCl added to push the position of equilibrium to the left and keep the SbOCl in solution.

If a few drops of the SbCl₃(aq) were added to 300 mL of water, the solution would turn cloudy. The HCl would be so dilute that the position of equilibrium would lie to the right, and a cloudy precipitate of antimony oxychloride would form.

7 0

3 years ago

What is the production of H2O2(aq) + 2H+(aq) + 2I–(aq)

Nata [24]

Answer: math is gay

Explanation:

6 0

2 years ago

Read 2 more answers

Calculate the number of grams in 4.56 x 1026 atoms of sodium phosphate. Be sure to balance the charges of sodium phosphate. Help

zalisa [80]

Answer:

124225.91 g of Na₃PO₄

Explanation:

From the question given above, the following data were obtained:

Number of atoms of Na₃PO₄ = 4.56×10²⁶ atoms

Mass of Na₃PO₄ =?

From Avogadro's hypothesis,

6.02×10²³ atoms = 1 mole of Na₃PO₄

Next, we shall determine the mass of 1 mole of Na₃PO₄. This can be obtained as follow:

1 mole of Na₃PO₄ = (23×3) + 31 + (16×4)

= 69 + 31 + 64

= 164 g

Thus,

6.02×10²³ atoms = 164 g of Na₃PO₄

Finally, we shall determine the mass of Na₃PO₄ that contains 4.56×10²⁶ atoms. This can be obtained as follow:

6.02×10²³ atoms = 164 g of Na₃PO₄

Therefore,

4.56×10²⁶ atoms = (4.56×10²⁶ × 164)/6.02×10²³

4.56×10²⁶ atoms = 124225.91 g of Na₃PO₄

Therefore, 124225.91 g of Na₃PO₄ contains 4.56×10²⁶ atoms

4 0

2 years ago

Which of the following represents the electron configuration of rhodium

nordsb [41]

Answer:

i need a picture to solve

Explanation:

3 0

3 years ago

How many moles are equal to 1.3 x 1024 atoms of aluminum?

marshall27 [118]

Answer:

<h3>The answer is 2.16 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{1.3 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 2.159468...$

We have the final answer as

<h3>2.16 moles</h3>

Hope this helps you

8 0

2 years ago