Question

Imagine that two unlinked autosomal genes with simple dominance code in goats for size, where T is tall and t is short, and for color, where R is red and r is tan. If a short, tan male goat mates with a tall, red female goat of an unknown genotype, what is the probability that they would produce short, tan offspring?
and....

One of a pea plants is homozygous recessive for both genes, resulting in the cross Yy Rr × yy rr. Calculate the percentage of green and round offspring.

Answer 1

Answer:

(A)  0.0625

(B)  25%

Explanation:

A

Given that ;

T is tall

t is short

R is red

r is tan.

If a short, tan male goat mates with a tall, red female goat of an unknown genotype;

Let's take it one after the other;

A short tan male goat = ttrr

The female goat is an unknown genotype, we will have to determine that but we were told that it is tall and red

∴ For tall it is T and red is R;

Definitely, the female genotype should be T_ R_;

the probability genotype of the female for each allele is either:

-   TT or Tt

-   RR or Rr

However,  from above;

the probability that the female will be Tt = $\frac{1}{2}$

the probability that the female will be Rr = $\frac{1}{2}$

the probability that the recessive allele 't' will be transferred to the offspring = $\frac{1}{2}$

the probability that the recessive allele 'r' will be transferred to the offspring = $\frac{1}{2}$

∴ the probability that they would produce short, tan offspring (ttrr) will be;

= $(\frac{1}{2})^{4}$

= $(\frac{1}{16})$

= 0.0625

(B)

One of a pea plants is homozygous recessive for both genes, resulting in the cross Yy Rr × yy rr. Calculate the percentage of green and round offspring.

For Color, Let;

Y = Yellow

y = Green

For shape, Let;

R = Round

r = wrinkled

If a cross occur between  Yy Rr × yy rr.   (i.e yellowround and green wrinkled)

the percentage of green and round offspring will be;

If Yy Rr self crossed; we have the following traits (YR, Yr, yR, yr)

yy rr will result to (yr, yr)

                   YR                    Yr                    yR                    yr

yr                 YyRr                 Yyrr                 yyRr                 Yyrr

yr                 YyRr                 Yyrr                 yyRr                 Yyrr

                   Yellow              Yellow            Green              Green

                   Round               Wrinkled        Round              Wrinkled

Therefore, the percentage of Green and Round offsprings from above is:

= $\frac{2}{8}*100%$%

=$\frac{1}{4}*100$%

= 25%