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serg [7]
3 years ago
5

X−1.2=3 what is x HELP ASAP K-12 8TH GRADE

Mathematics
2 answers:
Shalnov [3]3 years ago
4 0

Hello! :)

To find what is x we will add 1.2 to both sides

x - 1.2 + 1.2 = 3 + 1.2

x = 4.2

Hope this helped you!

THEDIPER

NARA [144]3 years ago
3 0

hi! here is ur  answer

x-1.2=3

x=3+1.2

x=4.2

hope it helps you!

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Hatshy [7]

Answer:

1, 3, and 4 would be correct answers

Step-by-step explanation:

1.) <u>-x - 2x - 3y - 2y + 1 + 1 = -3x -5y + 2</u>

2.) -3x + 2y + 3y + 2 = -3x + 5y + 2

3.) <u>-3x - y - y - y - y - y + 2 = -3x - 5y + 2</u>

4.) <u>-x - x - x - y - y - y - y - y + 1 + 1 = -3x - 5y + 2</u>

5.) x + x + x + y + y + y + y + y + 1 + 1 = 3x + 5y + 2

Hope this helps!

5 0
2 years ago
In the figure, all, and both lines are intersected by transversal &amp; Complete the statements to prove that m≤1 = m25.
m_a_m_a [10]

First blank: Substitution or transitive property of equality

Second blank: Subtraction property of equality

7 0
2 years ago
What is the length of the arc when the degree measure is 60° and the radius is 7?
shepuryov [24]
Inscribed angle =1/2 arc
4 0
3 years ago
The school chorus has 52 students, which represents 26% of the seventh graders. How many total students are in the seventh grade
Sedaia [141]

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there are 200 students in the 7th grade.

7 0
2 years ago
slader (a) Find parametric equations for the line through (4, 1, 8) that is perpendicular to the plane x − y + 4z = 2. (Use the
Pavel [41]

Answer:

(x(t), y(t), z(t)) = (4 + t, 1 - t, 8 + 4t)

xy - plane    (x, y, z) = (2, -1, 0)

yz - plane    (x, y, z) = (0, 5, -8)

xz - plane     (x, y, z) = (5, 0, 12)

Step-by-step explanation:

The given point (x, y ,z) = (4, 1, 8)

The plane x -y + 4z = 2

Normal vector (n) = < 1, -1, 4 >

The equation of line through point (4, 1, 8) and the plane is:

(x(t), y(t), z(t)) = (4, 1, 8) + t(1, -1, 4)

(x(t), y(t), z(t)) = (4 + t, 1 - t, 8 + 4t)

Any point on the line P(x, y, z) = ( 4 + t, 1 - t, 8 + 4t)

xy-Pane ⇒ z = 0

8 + 4t = 0

4t = - 8

t = -8/4

t = -2

∴

(x, y, z) = (4 - 2, 1 - 2, 8 + 4(-2))

(x, y, z) = (2, -1, 0)

yz-plane ⇒ x = 0

4 + t = 0

t = -4

∴

(x, y, z) = (4 + (-4) , 1-(-4), 8 + 4(-4)

(x, y, z) = (0, 5, -8)

xz-plane ⇒ y = 0

1 - t = 0

-t = -1

t = 1

∴

(x, y, z) = ( 4 + 1, 1 - 1, 8 + 4(1) )

(x, y, z) = (5, 0, 12)

6 0
3 years ago
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