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3 years ago

It is known that solve for the value of x algebraically.

Mathematics

1 answer:

otez555 [7]3 years ago

7 0

Answer:

x + 3 = 9 (original equation )

x = 9 – 3 (take the constant term to the other side so that the variable x is isolated.)

x = 6

So x = 6 is the required solution to the equation.

Step-by-step explanation:

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Zach puts $1000 in a savings account earning 5% simple interest for five years how much interest has he earned at the end of the

loris [4]

Answer:

$250

Step-by-step explanation:

The formula for simple interest is I = PRT, where I= interest earned or paid, P = principal deposited or borrowed, R = interest rate as a decimal, and T = time in years.

I = PRT

I = (1000)(0.05)(5)

I = 250

7 0

3 years ago

I NEED HELP ASAP!!!

KonstantinChe [14]

A because they add up to 190 then you subtract that from 360 and get 170

3 0

3 years ago

Read 2 more answers

I think of a number, I halve it then take away 4 and answer is 6 ,What was my number

Juliette [100K]

20 because if you take 20 half it that would be 10 then take away 4 that would then equal 6.

6 0

3 years ago

X = <br><br> A)6 2/3<br> B)9<br> C)12

disa [49]

I think the answer would be (C) 12 because when you lay the line measuring 5 - 4 flat you can see that it is not covering line x completely. When 3 to the new line of 9 you can see that it fits. Hope this helps!

4 0

3 years ago

A random sample of 1000 people was taken. Four hundred fifty of the people in the sample favored Candidate A. The 95% confidence

KatRina [158]

Answer:

The 95% confidence interval would be given (0.419;0.481).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

X=450 represent the people in the sample favored Candidate A

$\hat p=\frac{450}{1000}=0.45$ estimated proportion of people in the sample favored Candidate A

$\alpha=0.05$ represent the significance level

Confidence =0.95 or 95%

p= population proportion of people in the sample favored Candidate A

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.5=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.45 - 1.96 \sqrt{\frac{0.45(1-0.45)}{1000}}=0.419$

$0.45 + 1.96 \sqrt{\frac{0.45(1-0.45)}{1000}}=0.481$

And the 95% confidence interval would be given (0.419;0.481).

We are confident (95%) that about 41.9% to 48.1% of the people are favored Candidate A.

3 0

3 years ago