Molality= mol/ Kg
if we assume that we have 1 kg of water, we have 3.19 moles of solute.
the formula for mole fraction --> mole fraction= mol of solule/ mol of solution
1) if we have 1 kg of water which is same as 1000 grams of water.
2) we need to convert grams to moles using the molar mass of water
molar mass of H₂O= (2 x 1.01) + 16.0 = 18.02 g/mol
1000 g (1 mol/ 18.02 grams)= 55.5 mol
3) mole of solution= 55.5 moles + 3.19 moles= 58.7 moles of solution
4) mole fraction= 3.19 / 58.7= 0.0543
Answer:
B-2
Explanation:
In the graph you can so that two of the shapes ae fully black, that means that they are color blind, the half colored ones means they are a carrier but they aren't color blind. So two males in the offspring are color blind.
First, we need to convert the grams of gold into mole using the molar mass (molecular weight) of gold, and then into particles using avogadro's number (1 mol= 6.02 x 10^23)
molar mass of gold= 197 grams/ mole
100.0 grams (1 mole/ 197 grams) x (6.02 x 10^23 particles/ 1 mole) = 3.06 x 10^23
Answer:
The reason why Stephanie -who does not consume alcohol but was medicated for coughing- had a high reading when she had her preliminary breath test (PBT) is because the medication contained molecules similar to ethanol (option C).
Explanation:
Breath alcohol content (BAC) is a measure that is performed through the use of special devices, such as the brethalizer, an analyzer for detecting blood alcohol in drivers. Ethanol is a volatile product that, when found in the blood, is partially eliminated by the airways.
<u>The use of certain types of medications may cause a high reading on the breathalyzer because they contain ethanol</u>. This is likely to have happened to Stephanie who was using a cough medicine -which usually has a low ethanol content- and got a positive reading on the breathalyzer.
Explanation:
It is known that atomic number of carbon is 6 and its electronic configuration is 
. This means that in its neutral state it contains 2 electrons in its s-orbital and 2 electrons in its p-orbital.
After excitation there will be one electron present in its s-orbital and three electrons present in p-orbital.
Therefore, after the hybridization there will be in total 2 sp hybrid orbitals, 2 p-orbitals and zero s-orbital.
