Question

A sample of gas has a volume of 100. L at 17 °C and 800. torr. To what temperature must the gas be cooled in order for its volume to become 50.0 L at a pressure of 600. torr? Your answer will need to be in Kelvin.
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Answer 1

Answer:

108.81 K

Explanation:

First convert 17 °C to Kelvin:

• 17 + 273.16 = 290.16 K

Assuming ideal behaviour, we can solve this problem by using the combined gas law, which states that at constant composition:

• P₁V₁T₂=P₂V₂T₁

Where in this case:

• P₁ = 800 torr

• V₁ = 100 L

• T₂ = ?

• P₂ = 600 torr

• V₂ = 50 L

• T₁ = 290.16 K

We input the data:

• 800 torr * 100 L * T₂ = 600 torr * 50 L * 290.16 K

And solve for T₂:

• T₂ = 108.81 K