The answer is the last option "Respiration"
Answer:
The capacitance per unit length is ![5.06\times10^{-11}\ F/m](https://tex.z-dn.net/?f=5.06%5Ctimes10%5E%7B-11%7D%5C%20F%2Fm)
(b) is correct option.
Explanation:
Given that,
Radius a= 2.50 mm
Radius b=7.50 mm
Dielectric constant = 3.68
Potential difference = 120 V
We need to calculate charge per length for the capacitance
Using formula of charge per length
![\lambda=\dfrac{4\pi\epsilon_{0}\Delta V}{2 ln(\dfrac{r_{2}}{r_{1}})}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B4%5Cpi%5Cepsilon_%7B0%7D%5CDelta%20V%7D%7B2%20ln%28%5Cdfrac%7Br_%7B2%7D%7D%7Br_%7B1%7D%7D%29%7D)
Put the value into the formula
![\lambda=\dfrac{120}{9\times10^{9}\times2 ln(\dfrac{7.50\times10^{-3}}{2.50\times10^{-3}})}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B120%7D%7B9%5Ctimes10%5E%7B9%7D%5Ctimes2%20ln%28%5Cdfrac%7B7.50%5Ctimes10%5E%7B-3%7D%7D%7B2.50%5Ctimes10%5E%7B-3%7D%7D%29%7D)
![\lambda=6.068\times10^{-9}\ C/m](https://tex.z-dn.net/?f=%5Clambda%3D6.068%5Ctimes10%5E%7B-9%7D%5C%20C%2Fm)
We know that,
![\lambda=\dfrac{Q}{L}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7BQ%7D%7BL%7D)
We need to calculate the capacitance per unit length
Using formula of capacitance per unit length
![C=\dfrac{\dfrac{Q}{L}}{\Delta V}](https://tex.z-dn.net/?f=C%3D%5Cdfrac%7B%5Cdfrac%7BQ%7D%7BL%7D%7D%7B%5CDelta%20V%7D)
![C=\dfrac{6.068\times10^{-9}}{120}](https://tex.z-dn.net/?f=C%3D%5Cdfrac%7B6.068%5Ctimes10%5E%7B-9%7D%7D%7B120%7D)
![C=5.06\times10^{-11}\ F/m](https://tex.z-dn.net/?f=C%3D5.06%5Ctimes10%5E%7B-11%7D%5C%20F%2Fm)
Hence, The capacitance per unit length is ![5.06\times10^{-11}\ F/m](https://tex.z-dn.net/?f=5.06%5Ctimes10%5E%7B-11%7D%5C%20F%2Fm)
Answer: 2.86 m
Explanation:
To solve this question, we will use the law of conservation of kinetic and potential energy, which is given by the equation,
ΔPE(i) + ΔKE(i) = ΔPE(f) + ΔKE(f)
In this question, it is safe to say there is no kinetic energy in the initial state, and neither is there potential energy in the end, so we have
mgh + 0 = 0 + KE(f)
To calculate the final kinetic energy, we must consider the energy contributed by the Inertia, so that we then have
mgh = 1/2mv² + 1/2Iw²
To get the inertia of the bodies, we use the formula
I = [m(R1² + R2²) / 2]
I = [2(0.2² + 0.1²) / 2]
I = 0.04 + 0.01
I = 0.05 kgm²
Also, the angular velocity is given by
w = v / R2
w = 4 / (1/5)
w = 20 rad/s
If we then substitute these values in the equation we have,
0.5 * 9.8 * h = (1/2 * 0.5 * 4²) + (1/2 * 0.05 * 20²)
4.9h = 4 + 10
4.9h = 14
h = 14 / 4.9
h = 2.86 m
Kinetic energy would increase sir.
What work??? I don’t see anything