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ser-zykov [4K]
3 years ago
12

A 76.5 kg cross-country skier skiing on unwaxed skis along dry snow at a constant speed of 4.00 m/s experiences a force of frict

ion of -60.0 N.  What is the coefficient of friction between unwaxed skis and dry snow?
a. 0.08
b. 0.78
c. 1.28
d. 12.5
Physics
1 answer:
NeX [460]3 years ago
6 0
The force of friction = (weight) x (coefficient of friction)

Skier's weight = (mass) x (gravity) = (76.5) x (9.8) = 749.7 N

Force of friction = (749.7) x (coefficient of friction) = 60.0 N

Coefficient of friction = 60 / 749.7 = <u>0.08 </u> (rounded)

Choice-'A' is the closest choice offered.
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Answer:

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Explanation:

Given the data in the question;

speed of the spacecraft as it moves past the is 0.6 times the speed of light

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Now, from time dilation;

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t = Δt₀ / √( 1 - ( v/c )² )

we substitute

t = 3.2 / √( 1 - ( 0.6c / c )² )

t = 3.2 / √( 1 - ( 0.6 )² )

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t = 3.2 / √0.64

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t = 4 seconds

Therefore, the time interval that an earth observer measures is 4 seconds

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