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DiKsa [7]
3 years ago
7

Iron(II) is available to bond with chloride ion. How many of each type of ion will bond to form an ionic compound?

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
7 0

Answer:

D) 1 iron(II), 2 chloride

Explanation:

Iron II chloride is the compound; FeCl2. It is formed as follows, ionically;

Fe^2+(aq) + 2Cl^-(aq) -----> FeCl2

The formation of one mole of FeCl2 involves the reaction one mole of iron and two moles of chloride ions. This means that in FeCl2, the ratio of iron to chlorine is 1:2 as seen above.

Therefore there is one iron II ion and two chloride ions in each mole of iron II chloride, hence the answer.

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Answer:

0.75 M

Explanation:

Molarity = moles of solute / liters of solution

so;

Molarity = \frac{1.5 Moles}{2.0 Liters}

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513.975g

Explanation:

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Answer:

The pencil box is too far away from the magnet to make it move.

Explanation:

The most likely scenario here is that the pencil box is too far away from the magnet to make it move.

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Outside the force field, a magnet has no effect on a magnetic body.

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