Answer: 98.36g/mol
Explanation:Please see attachment for explanation
Balanced equation:
<span>2 NO + 5 H2 ------> 2 NH3 + 2 H2O
</span>
<span>2 moles NO react with 5 moles H2 to produce 2 moles NH3
</span>
<span>Molar mass of NO = 30.00 g/mol </span>
<span>86.3g NO = 86.3/30.00 = 2.877 moles of NO </span>
<span>This will require: 2.877*5 / 2 = 7.192 moles of H2 </span>
<span>Molar mass of H2 = 2 g/mol </span>
<span>25.6g H2 = 25.6/2 = 12.7 mol H2. </span>
<span>You have excess H2 means the NO is limiting </span>
<span>From the balanced equation: </span>
<span>2 moles of NO will produce 2 moles of NH3 </span>
<span>2.877 moles of NO will produce 2.877 moles of NH3 </span>
<span>Molar mass NH3 = 17g/mol </span>
<span>Mass NH3 produced = 2.877 * 17 = 48.91g
Hence the yield is = 48.91 g ~ 49 g</span>
<u>Answer:</u> The mass of iron (II) oxide that must be used in the reaction is 30.37
<u>Explanation:</u>
The given chemical reaction follows:
By Stoichiometry of the reaction:
When 635 kJ of energy is released, 6 moles of iron (II) oxide is reacted.
So, when 44.7 kJ of energy is released, 
of iron (II) oxide is reacted.
Now, calculating the mass of iron (II) oxide by using the equation:
Moles of iron (II) oxide = 0.423 moles
Molar mass of iron (II) oxide = 71.8 g/mol
Putting values in above equation, we get:
Hence, the mass of iron (II) oxide that must be used in the reaction is 30.37
Protons + and electrons - must be equal
3 moles of C has a mass of 36, 3 moles of He is 12
so the answer is :
The carbon sample would have three times the mass of the helium sample
hope this helps
Answer:
200cc of 5N HCl were diluted
Explanation:n
<em>Assuming the solution was diluted to prepare a 1N HCl solution:</em>
The HCl was diluted from 5N to 1N, that is a dilution of:
5N / 1N = 5 times
As the total volume of the diluted solution is 1L = 1000mL = 1000cc the amount of the concentrated solution was:
1000cc / 5 =
<h3>200cc of 5N HCl were diluted</h3>
