Answer:
1. 1.62×10¹¹ nm
2. 4.8×10¹⁴ Hz
Explanation:
1. Determination of the wavelength.
We'll begin by converting 1.85 MHz to Hz. This can be obtained as follow:
1 MHz = 10⁶ Hz
Therefore,
1.85 MHz = 1.85 MHz × 10⁶ Hz / 1 MHz
1.85 MHz = 1.85×10⁶ Hz
Next, we shall determine the wavelength of the electromagnetic radiation. This can be obtained as follow:
Frequency (f) = 1.85×10⁶ Hz
Velocity of electromagnetic radiation (v) = 3×10⁸ m/s
Wavelength (λ) =?
v = λf
3×10⁸ = λ × 1.85×10⁶
Divide both side by 1.85×10⁶
λ = 3×10⁸ / 1.85×10⁶
λ = 162.16 m
Finally, we shall convert 162.16 m to nm. This can be obtained as follow:
1 m = 10⁹ nm
Therefore,
162.16 m = 162.16 m × 10⁹ nm / 1 m
162.16 m = 1.62×10¹¹ nm
Thus, the wavelength of the electromagnetic radiation is 1.62×10¹¹ nm
2. Determination of the frequency.
We'll begin by converting 625 nm to m. This can be obtained as follow:
1 nm = 10¯⁹ m
Therefore,
625 nm = 625 nm × 10¯⁹ m / 1 nm
625 nm = 6.25×10¯⁷ m
Finally, we shall determine the frequency the visible light as follow:
Wavelength (λ) = 6.25×10¯⁷ m
Velocity of light (v) = 3×10⁸ m/s
Frequency (f) =?
v = λf
3×10⁸ = 6.25×10¯⁷ × f
Divide both side by 6.25×10¯⁷
f = 3×10⁸ / 6.25× 10¯⁷
f = 4.8×10¹⁴ Hz
Therefore, the frequency of the visible light is 4.8×10¹⁴ Hz
