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77julia77 [94]
3 years ago
11

4. Separate 77 into two parts so that one part is 4 less than twice as much as the other. Find each part.​

Mathematics
1 answer:
Igoryamba3 years ago
8 0

Answer:

50,27

Step-by-step explanation:

let the parts be x and y

x+y=77

x=2y-4

substitute

2y-4+y=77

3y=77+4

3y=81

y=81/3=27

x=2×27-4=54-4=50

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Write a problem you can solve using the fractions 5/8 and 1 2/7. Explain how you can solve by simplifying a complex fraction. Sh
AnnyKZ [126]

Answer:

5/8 + 9/7 +107/56

Step-by-step explanation:

5/8+9/7=5x7/8x7+ 9x8/7x8=35/56 + 72/56= 35+52/56=107/56

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3 0
3 years ago
Read 2 more answers
Hello,
qaws [65]

Answer:

1/4

Step-by-step explanation:

the square is divided into 4 pieces and only one of them is shaded  

7 0
3 years ago
Does anyone know the answer to this?
PolarNik [594]

Answer:

(B) The exponents should be subtracted by the quotient rule of exponents

Step-by-step explanation:

Let's examine how this was solved.

(\frac{4^2 4^3}{4^{-5}})^2

He first rose everything in the parentheses to the second power, which is just multiplying all the exponents by 2. This is correct.

\frac{4^4 4^6}{4^{-10}}

He then combined the numerator exponents. Exponent rules say that a^b \cdot a^c = a^b+c, so he should have ended up with 4^{10}, which he did. This is correct.

\frac{4^{10}}{4^{-10}}

Now, what he did in the final step is wrong. He added the exponents. However, exponent rules tell us that when we have \frac{a^b}{a^c}, it equals a^{b-c}.

10 - (-10) = 10+10 = 20

So the final answer should have been 4^{20}

Hope this helped!

6 0
4 years ago
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