1, 5, 9, 13...

1 answer:

Kruka [31]3 years ago

7 0

C. ................jhAn

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Andre45 [30]

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Harman [31]

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enot [183]

Answer:

$\boxed{\ g(x)=\dfrac{1}{4}|x-2|+1 \ }$

Step-by-step explanation:

As the graph is passing via (2,1) and (-6,3)

$g(x)=\dfrac{1}{4}|x-2|+1$

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3 years ago