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iogann1982 [59]
3 years ago
13

(1st pic) What is the equation of the line shown in this graph?

Mathematics
1 answer:
vredina [299]3 years ago
4 0

Answer:

For figure 1: The equation of a line is y=1

For figure 2: The equation of a line is y=(-4)x+1

For figure 3:The equation of a line is y=\frac{-5}{2}x+5

Step-by-step explanation:

The equation of line slope-intercept form is given by y=mx+c

Where m is the slope of the line and c is the y-intercept.

For figure 1:

Here, Line is parallel to x-axis

Hence, Slope m=0

Also, Line passing to y axis at (0,1)

Y-intercept is c=1

Therefore,

The equation of line is

y=0x+1

y=1

For figure 2:

Figure show a line passing through point (1,-3) and (-1,5)

The slope of the line is given by m=\frac{Y2-Y1}{X2-X1}

Using given points to find out the slope of a line

m=\frac{Y2-Y1}{X2-X1}

m=\frac{5-(-3)}{(-1)-1}

m=\frac{8}{-2}

m=(-4)

Also, Line is intersecting y-axis at (0,1)

Hence, c=1

We can write the equation of line as

y=mx+c

y=(-4)x+1

Thus, The correct option is D). y=(-4)x+1

For figure 3:

From the figure, a line is passing through points (-2,0) and (0,5)

The slope of the line is given by m=\frac{Y2-Y1}{X2-X1}

Using given points to find out the slope of a line

m=\frac{Y2-Y1}{X2-X1}

m=\frac{5-0}{0-(-2)}

m=\frac{-5}{2}

Also, Line is intersecting y-axis at (0,5)

Hence, c=5

We can write the equation of line as

y=mx+c

y=\frac{-5}{2}x+5

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