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Sergio039 [100]
3 years ago
9

Why do electrons rather than protons make up the flow of charge in a metal wire?

Physics
1 answer:
andrew-mc [135]3 years ago
6 0
Protons are tightly bound to the nucleus of atoms, and the nucleus is
'shielded' from the outside world by the 'cloud' of electrons around it. 
It takes a lot of energy to separate a proton from the nucleus.  When
that happens, it's a 'radioactive' or a 'nuclear' event, and the atom has
changed into an atom of a different substance.  This isn't something
that's happening around us very often.

On the other hand, the electrons are on the outside of the atom, and
it's rather easy to convince an electron to leave its atom and flow off
to somewhere else.
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Plzzzz help me!! Plz don’t guess, than you!!
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Answer:

The answer is W

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3 years ago
What is the most likely outcome of increasing the number of slits per unit distance on a diffraction grating?1) lines become nar
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It's important to know that diffraction gratings can be identified by the number of lines they have per centimeter. Often, more lines per centimeter is more useful because the images separation is greater when this happens. That is, the distance between lines increases.

<h2>Therefore, the answer is 2.</h2>
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2 years ago
Water exits a garden hose at a speed of 1.2 m/s. If the end of the garden hose is 1.5 cm in diameter and you want to make the wa
Katarina [22]

Answer:

A 93%

Explanation:

P_1=P_2 = Pressure will be equal at inlet and outlet

\rho = Density of water = 1000 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

v_1 = Velocity at inlet = 1.2 m/s

v_2 = Velocity at outlet

r_1 = Radius of inlet = \dfrac{1.5}{2}=0.75\ cm

r_2 = Radius of outlet

From Bernoulli's relation

P_1+\dfrac{1}{2}\rho v_1^2+\rho gh_1=P_2+\dfrac{1}{2}\rho v_2^2+\rho gh_2\\\Rightarrow \dfrac{1}{2}\rho v_1^2+\rho gh_1=\dfrac{1}{2}\rho v_2^2+\rho gh_2\\\Rightarrow v_2=\sqrt{2(\dfrac{1}{2}v_1^2+gh_1-gh_2)}\\\Rightarrow v_2=\sqrt{2(\dfrac{1}{2}1.2^2+9.81\times 15)}\\\Rightarrow v_2=17.19709\ m/s

From continuity equation

A_1v_1=A_2v_2\\\Rightarrow \pi r_1^2v_1=\pi r_2^2v_2\\\Rightarrow r_2=\sqrt{\dfrac{r_1^2v_1}{v_2}}\\\Rightarrow r_2=\sqrt{\dfrac{0.0075^2\times 1.2}{17.19709}}\\\Rightarrow r_2=0.00198\ m

The fraction would be

\dfrac{A_1-A_2}{A_1}\times 100=\dfrac{r_1^2-r_2^2}{r_1^2}\times 100\\ =\dfrac{0.0075^2-0.00198^2}{0.0075^2}\times 100\\ =93.0304\ \%

The fraction is 93.0304%

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Look at Figure 2. Describe the motion of the object in Graph A
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The graphs show distance versus time data. For graph A, we can say that velocity is constant until it reaches time of 8 seconds. And a constant velocity is again exhibited starting at time 12 seconds. For graph B, the velocity is changing as time pass by since  the slope is changing. At time of 2 seconds, graph A has greater velocity since it has a steeper slope.
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