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spin [16.1K]
3 years ago
10

Learning Task 2: Write the words that can be associated with the ''Music During Classical Era''. You may ask help from the membe

rs of your family or search the internet if you have the means. Do this activity in your notebook.
Physics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

classical

concert

exposition

orchesta

devolopment

recapitulation

sympathy

sonata

sinfonia

soloist

Explanation:

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Find h , the maximum height attained by the projectile. express the maximum height in terms of v 0 , θ , and g .
lutik1710 [3]

solution:

the utmost height would be comprehensive while y'(t)=0. (on the suitable of the trajectory, the y speed is 0.)y(t)=(88sin20)t-16t^2 y'(t)=88sin20-32t So y'(t)=0 while t=(88sin20)/32

3 0
3 years ago
From lowest energy to highest energy, which of the following correctly orders the different categories of electromagnetic radiat
Valentin [98]

Answer: The answer is "C"

Explanation:

The electromagnetic waves are arranged in the increasing wavelength and energy by the following order;

Radio waves has the lowest energy and wavelength but of the highest frequency.

The Infra-red rays follows the visible light follows, the ultraviolet ray follows, the X-ray follows and then the Gamma-ray has the highest energy and wavelength but the lowest frequency.

Therefore the answer is C, radio, infra, visible, ultraviolet, x-ray, gamma.

4 0
3 years ago
Read 2 more answers
Rank them from fastest to slowest in how quickly each warms up: (a) steel, 450 j/kgââc ; (b) aluminum, 910 j/kgââc ; (c) copper,
s2008m [1.1K]
<span>The rate of conductivity is different among different substances, like aluminum, steel, and copper. Aluminum conducts heat the fastest at 910 j/kgaac. Steel is next and conducts heat at 450 j/kgaac. Copper conducts heat the slowest at 390 j/kgaac.</span>
5 0
3 years ago
______ consist of one large main root with smaller roots branching off, while _____ consist of several main roots that branch of
rodikova [14]
Stems and leaves is the answer. Jessica you are in my class right ?
7 0
3 years ago
A 1-mCi source of^60 Co is placed in the center of a cylindrical water-filled tank with an inside diameter of 20 cm and depth of
LenKa [72]

To solve this problem we need the concepts of Energy fluency and Intensity from chemical elements.

The energy fluency is given by the equation

\Psi=4RcE\pi

Where

\Psi =The energy fluency

c = Activity of the source

r = distance

E = electric field

In the other hand we have the equation for current in materials, which is given by

I= I_0 e^{-\mu_{h20}X_{h2o}} e^{-\mu_{Fe}X_{Fe}}

Then replacing our values we have that

I = 1*10^{-3} * 3.3*10^{10} * e ^{-0.06*1.1} e^{-0.058*7.861}

I = 1.3*10^7 Bq

We can conclude in this part that 1.3*10^7Bq is the activity coming out of the cylinder.

Now the energy fluency would be,

\Psi = \frac{cE}{4\pir^2}

\Psi = \frac{1.3*10^7*2*1.25}{4\pi*11^2}

\Psi = 2.14*10^4 MeV/cm^2.s

The  uncollided flux density at the outer surface of the tank nearest the source is \Psi = 2.14*10^4 MeV/cm^2.s

6 0
2 years ago
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