Answer:
–77867 m/s/s.
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 34.5 m/s
Final velocity (v) = –23.9 m/s
Time (t) = 0.00075 s
Acceleration (a) =?
Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:
Acceleration = (final velocity – Initial velocity) /time
a = (v – u) / t
With the above formula, we can obtain acceleration of the ball as follow:
Initial velocity (u) = 34.5 m/s
Final velocity (v) = –23.9 m/s
Time (t) = 0.00075 s
Acceleration (a) =?
a = (v – u) / t
a = (–23.9 – 34.5) / 0.00075
a = –58.4 / 0.00075
a = –77867 m/s/s
Thus, the acceleration of the ball is –77867 m/s/s.
Given that,
Acceleration, a = 9.71 m/s²
Force, F = 5050 N
mass, m = ?
Since, we know that
F=ma
m= F/a
m= 5050/9.71
m= 520.08 kg
The mass of hi car is 520.08 kilograms.
When it has been proven by science to be true.
Answer:
s = 45 m
Explanation:
The velocity given in the question is uniform. Hence, the formula for the uniform velocity shall be used here. The formula is given as follows:

where,
s = distance traveled away from the brother = ?
v = constant speed = 3 m/s
t = time taken = (0.25 min)(60 s/1 min) = 15 s
Therefore, using these values in the formula we get:

<u>s = 45 m</u>
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