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poizon [28]
3 years ago
15

Solve for: lim x>0- ((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX

Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0
2(x + delta x) = 2x + 2 delta x
so on top you have 2x + 2 delta x - 2x
which is 2 delta x
the delta x cancels out and you are left with just 2

so the limit is 2
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x²+5x+6.25 = 2+6.25
(x+2.5)² = 8.25

Take the square root of both sides:
√(x+2.5)² = √8.25
x + 2.5 = 2.87

Subtract 2.5 from both sides:"
x+2.5-2.5 = 2.87-2.5
x = 0.37

We have to take the positive and negative values for solutions, however, since a square root has both positive and negative answers.
4 0
3 years ago
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Lera25 [3.4K]

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Step-by-step explanation:

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How many solutions are there for the system x^2+4y^2=100 and 4y-x^2=-20
never [62]
There are 5 solutions for this system.

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Then equation the becomes : y^2 + y -20 =0
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Solve for y :  y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
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y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
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6 0
3 years ago
I will give the brainiest answer
Airida [17]

Answer:

D

Step-by-step explanation:

If you draw the shape in D and assemble it you will get the answer

btw please mark brainliest

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