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Vlad [161]
3 years ago
12

I'll give you branliest- A student uses a counting technique to estimate time. She counts "one one-thousand, two one-thousand, t

hree one-thousand" and so on. Her estimate for a 10-second interval is 9.28 seconds. Assuming her rate is constant, what will her estimate be for 120 seconds?
A. 111.36 seconds
B. 114.56 seconds
C. 119.28 seconds
D. 122.84 seconds
Physics
2 answers:
choli [55]3 years ago
8 0

Answer:

A

Explanation:

Scrat [10]3 years ago
7 0
<h2><em>the correct answer is </em></h2><h2><em>A) 111.36 seconds</em></h2><h2><em>HOPE IT HELPS (◕‿◕✿) </em></h2>
You might be interested in
I really need help on this question!
LUCKY_DIMON [66]

Answer: C, 0.0021 seconds.

7 0
3 years ago
A factory worker pushes a 30.0kg crate a distance of 4.4 m along a level floor at constant velocity by pushing downward at an an
andre [41]

Answer:

1)  F = 94.58 N , 2) W1 = 360.4 J , 3)  W2 = -360.4 J , 4) W3 =0

Explanation:

1- To find the value of the force, let's use Newton's second law, where in the x-axis we have the applied force and the friction force that opposes the movement and the axis and we have the normal and the weight, look at the attached to see A free body diagram.

We see that the applied force (F) must be decomposed

     Cos θ = Fx / F

     Fx = f cos θ

     sinθ = Fy / F

     Fy = F sin θ

As the box moves at constant speed the acceleration is zero

X axis

      Fx-fr 0 = 0

      Fx = fr

      fr = μ N

      F cos T = μ N

      F cos T = μ N

Axis y

      N -W- Fy = 0

      N- F sin θ = mg

Let's write the equation system and solve it

      F cos θ = μ N

      N - F sin θ = mg                

      N = mg + F sinθ         (1)

      F cos θ = μ (mg + F sin θ)

      F (cos θ - μ Sin θ) = μ mg

      F (cos 30 - 0.24 sin 30) = 0.24 30.0 9.8

      F = 70.56 / 0.746

      F = 94.58 N

This is the value of the force applied

2- The work is defined as the scalar product of the force by the distance traveled, in this case as we have the components of the force the only one that performs work is the Enel X-axis component, because with the other the angle is 90º and the cosine of 90 is zero

      W1 = Fx X

      W1 = 94.58 cos 30 4.4

      W1 = 360.4 J

3- Let's calculate the value of the friction force

      fr = μ N

The value of normal can be found in equation 1

      N = mg + F sin θ

      N = 30.0 9.8 + 94.58 sin 30

      N = 341.3 N

      fr = 0.24 341.3

      fr = 81.9 N

Now we can calculate the work, but let's look at the angle between the displacement and the friction force that is 180º so the cosine of 180 = -1

     W2 = - fr X

     W2 = - 81.9 4.4

     W2 = -360.4 J

4- The normal one has a direction perpendicular to the displacement, so its angle is 90º and the cos 90 = 0, which implies that the work is zero

        W3 =0

5- To calculate total work we just have to add the work of each force

      W all = W1 + W2 + WN + Ww

      W all = 360.4 + (- 360.4) + 0+ 0

      W all = 0

4 0
4 years ago
A Car travel at a speed of 200 km/hr. How far it will go in 15 mins? 27.7 km 66.1 km7.70 km50.0 km8.33 km"
erastovalidia [21]

Answer:

So car will go 50 km in 15 minutes

Explanation:

We have given speed of the car = 200 km/hour

Time t = 15 minutes

We know that 1 hour = 60 minute

So 15 minute = \frac{15}{60}=0.25hour

We have to find the distance

We know that distance = speed ×time = 200×0.25=50 km

So car will go 50 km in 15 minutes

So option (d) will be the correct option

7 0
4 years ago
Pls answer the question I will make you as brainiest​
Nadusha1986 [10]

Answer:

Answer in the drawing. Please mark me brainliest

4 0
3 years ago
At what speed do a bicycle and its rider, with a combined mass of 110 kgkg , have the same momentum as a 1400 kgkg car traveling
DanielleElmas [232]

Answer:

<h2><u>76.36m/s</u></h2>

Explanation:

Step one:

given data

let the mass of the rider be m,=110kg

let the velocity be v=?

let the mass of the car be M,=110kg

let velocity of the car V=6m/s

Step two:

the momentum of an object is given by the expression

P=mv

<em />

Step two:

<em>since the two the bicycle rider must have the same momentum as the car,</em>

<em>then we need to equate their momentum</em>

mv=MV

110*v=1400*6

110v=8400

divide both sides by 110 to find v

v=8400/110

v=76.36m/s

<u>The rider is expected to have a speed of 76.36m/s</u>

5 0
3 years ago
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