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Roman55 [17]
3 years ago
12

Given that two objects interact via some force, the accelerations of these two objects have the same magnitude but opposite dire

ctions. (Assume no other forces act on either object.)
True
False
Physics
1 answer:
frosja888 [35]3 years ago
7 0

Answer:

False.

Explanation:

Newton's 3rd Law tells us that if two objects interact via some force, then the value one exerts on the other have the same magnitude but opposite directions. Newton's 2nd Law tells us that the value of this force is F=ma. So, for two objects with different masses, if the forces they are exerting on each other are equal (as they must be by Newton's 3rd Law), the accelerations they are experimenting must necessarily be different.

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The length of a simple pendulum is 0.66 m, the pendulum bob has a mass of 310 grams, and it is released at an angle of 12 degree
lina2011 [118]
A) the periodic time is given by the equation;
 T= 2π√(L/g)
For the frequency will be obtained by 1/T (Hz)
T = 2 × 3.14 √ (0.66/9.81)
   = 6.28 × √0.0673
    = 1.6289 Seconds
Frequency = 1/T = f = 1/1.6289
 thus; frequency = 0.614 Hz

b)  The vertical distance, the height is given by
 h= 0.66 cos 12
 h = 0.65 m
Vertical fall at the lowest point = 0.66 - 0.65 = 0.01 m
Applying conservation of energy
energy lost (MgΔh) = KE gained (1/2mv²)
 mgh = 1/2mv²
  v² = 2gΔh = 2×9.81 × 0.01 
                   = 0.1962
v = 0.443 m/s

c) total energy = KE + GPE = KE when GPE is equal to zero (at the lowest point possible)
Thus total energy is equal to;
E = 1/2mv²
   = 1/2 × 0.310 × 0.443²
   = 0.0304 J


4 0
3 years ago
An empty elevator has a mass of 722 kg. It moves between floors at a maximum speed of 6.00 m/s. The elevator is stopped on the 2
FinnZ [79.3K]

Answer:

Explanation:

The lift is going down with acceleration

Initial speed u = 0

Final speed v = 6 m/s

distance s = 15.25 m

acceleration a = ?

v² = u² + 2 a s

6² = 0 + 2 x a x 15.25

a = 1.18 m /s²

Elevator is going down with acceleration  .

mg - T = ma where T is tension in the cable .

722 x 9.8 - T = 722 x 1.18

7075.6 - T = 851.96

T = 6223.64 N .

7 0
3 years ago
How much would a 15.0 kg object weigh on Neptune?
yan [13]
The gravity on Neptune is 11.15 m/s²
the gravity on earth is 9.81 m/s²
divide the Neptune and earth gravity we get 1.13
which means object on neptune is 1.13 heavier than earth
yield, weigh of the object on neptune is 1.13×15=17.04kg
5 0
3 years ago
Read 2 more answers
Two mass m1 and m2 lie on a frictionless surface. Between the two masses is a compressed spring, with spring constant k. The sys
max2010maxim [7]

Answer:

The spring was compressed the following amount:

\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }

Explanation:

Use conservation of energy between initial and final state, considering that the surface id frictionless, and there is no loss in thermal energy due to friction. the total initial energy is the potential energy of the compressed spring (by an amount \Delta x), and the total final energy is the addition of the kinetic energies of both masses:

E_i=\frac{1}{2} k\,(\Delta x)^2\\\\E_f=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2

E_i=E_f\\

\frac{1}{2} k\,(\Delta x)^2=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2\\k\,(\Delta x)^2=m_1\,v_1^2+ m_2\,v_2^2\\(\Delta x)^2=\frac{m_1\,v_1^2+ m_2\,v_2^2}{k} \\\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }

8 0
3 years ago
The spectral distribution of the radiation emitted by a diffuse surface may be approximated as follows. HW 2 Q2 (a) What is the
Ronch [10]

Answer:

a)<em> 2000 W/m²  </em><em>; </em>b) 636.94 W/m<em>².sr ; </em><em>c) </em>0.5

Explanation:

a)

The formula for calculation of total emissive power is:

Total emissive power = E = \int\limits^\alpha_0 E'<em>λdλ</em>

<em>                                    </em>= \int\limits^a_0(0)d<em>λ + </em>\int\limits^b_a(100)d<em>λ + </em>\int\limits^c_b(200)d<em>λ + </em>\int\limits^d_c(100)d<em>λ </em>\int\limits^e_d(0)d<em>λ</em>

<em>where a = 5; b = 10; c = 15; d = 20; e = 25</em>

<em>                                    = 0 +100(10-5) + 200(15-10) +100(20-15) + 0</em>

<em>                                    = 2000 W/m²</em>

b)

The formula for total intensity of radiation is:

I_{e} = E/π = 200/3.14 = 636.94 W/m<em>².sr  </em>

<em>c)</em>

Fo submissive power leaving the surface in range π/4 ≤θ≤π/2

[E(π/4 ≤θ≤π/2)]/E = \int\limits^f_0\int\limits^g_0\int\limits^i_h Icosθsinθ dθdΦdλ

where f = infinity, g=2π, h=π/4, i=π/2

By simplifying, we get

                           = (-1/2)[cos(2π/2)-cos(2π/2)]

                           = -0.5(-1-0)

                           =0.5

8 0
3 years ago
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