Answer:
u = 13.67 m/s
Explanation:
given,
window height = 2 m
window is 7.5 m off the ground on its path up
total distance from the ground to pass the window = 2 + 7.5 = 9.5 m
time taken to go past the window = 1.30 s
using equation of motion
u = 13.67 m/s
hence, the initial velocity of the ball is equal to 13.67 m/s
Answer:
L₁ = W×L / w
Explanation:
The scenario is shown in the image below.
<u>At the pivot point, the torque acting on this point must be zero so that there will be easy back and forth without the heavier child.</u>
<u>Torque created by lighter child + Torque created by the heavier child = 0</u>
Thus,
According to the axis system, the heavier child is left to the pivot (origin), so,
W×(- L ) + w× L₁ = 0
So,
<u>L₁ = W×L / w</u>
Answer:
C. 2.0 cm
Explanation:
The magnetic field around the wire at point M is given by Biot-Savart Law:
where,
B = Magnetic field = 50 μT = 5 x 10⁻⁵ T
I = current = 5 A
μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²
R = distance of point M from wire = ?
Therefore,
R = 0.02 m = 2 cm
Hence, the correct option is:
<u>C. 2.0 cm</u>