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konstantin123 [22]
3 years ago
15

Consider two insulating balls with evenly distributed equal and opposite charges on their surfaces, held with a certain distance

between the centers of the balls. Construct a problem in which you calculate the electric field (magnitude and direction) due to the balls at various points along a line running through the centers of the balls and extending to infinity on either side. Choose interesting points and comment on the meaning of the field at those points. For example, at what points might the field be just that due to one ball and where does the field become negligibly small?
Physics
1 answer:
goldenfox [79]3 years ago
6 0
Fbvb bb bb. B. Go cfcffc.
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Mama L [17]

Answer

about – 0.7

Explanation:

5 0
3 years ago
A basketball is rolling with a velocity of 0.5 meters/second relative to the ground and due north. A tennis ball is rolling with
Lisa [10]
Since the basketball and the tennis ball both travel to the same direction relative to the ground, the velocity of the basketball relative to the tennis ball is therefore the difference of their velocities.
                                     0.5 m/s - 0.25 m/s = 0.25 m/s
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The sky is blue because: Select one: a. the index of refraction for air is slightly larger for blue than for red b. atomic hydro
lapo4ka [179]

Answer:

a. the index of refraction for air is slightly larger for blue than for red

5 0
3 years ago
if the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?
damaskus [11]
I believe this is it
The centripetal force is given by
F = mv^2 / r
When v' = v/2,
F' = mv'^2/r = m(v/2)^2/r = mv^2/4r = F/4.
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7 0
3 years ago
Read 2 more answers
If a quasar is moving away from us at v/c = 0.8, what is the measured redshift?
Delicious77 [7]

Answer:

The measured redshift is z =2

Explanation:

Since the object is traveling near light speed, since v/c = 0.8, then we have to use a redshift formula for relativistic speeds.

z= \sqrt{\cfrac{c+v}{c-v}}-1

Finding the redshift.

We can prepare the formula by dividing by lightspeed inside the square root to both numerator and denominator to get

z= \sqrt{\cfrac{1+\cfrac vc}{1-\cfrac vc}}-1

Replacing the given information

z= \sqrt{\cfrac{1+0.8}{1-0.8}}-1

z= \sqrt{\cfrac{1.8}{0.2}}-1\\z= \sqrt{9}}-1\\z=3-1\\z=2

Thus the measured redshift is z = 2.

4 0
3 years ago
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